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jQuery Help

This is my current code, the quantity11 field has to have an input that is greater than 1 for the form to submit.  I have two other fields I need checked as well quantity12 and quantityreg.

<script type="text/javascript">
		function check() {
			var elements = document.getElementsByName("quantity11");


			for (var i=0; i<elements.length; i++) {

				var nmbr = parseInt(elements[i].value,10);
				if (nmbr < 1){
					alert("Please add at least 1 treat pack to your order to proceed.");
					return false;
				}
			}
			
			return true;
		}
	</script>

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 I need to add quantity11, quantity12, and quantityreg all together and then check to see if they are greater than 1 to return true.  How can I add them together on the 3rd line?
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Nathan Riley
Asked:
Nathan Riley
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1 Solution
 
Daniel Van Der WerkenIndependent ConsultantCommented:
I don't know. I think you should consider using a JQuery validator. There are probably more than one available, but after a quick search here's one that looks promising:

http://jqueryvalidation.org/

Simply use as this example provides:
http://jqueryvalidation.org/min-method
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Nathan RileyFounder/CTOAuthor Commented:
That method would work but I still need the 3 fields sum'd or added together before the check somehow.
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Nathan RileyFounder/CTOAuthor Commented:
I tried this approach but the code doesn't appear to work.
<script type="text/javascript">
		function check() {
			var element1 = document.getElementsByName("quantity11");
			var element2 = document.getElementsByName("quantity12");
			var element3 = document.getElementsByName("quantityreg");
			var elements = +element1 + +element2 + +element3;
			for (var i=0; i<elements.length; i++) {

				var nmbr = parseInt(elements[i].value,10);
				if (nmbr < 1){
					alert("Please add at least 1 treat pack to your order to proceed.");
					return false;
				}
			}
			
			return true;
		}
	</script>

Open in new window

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Nathan RileyFounder/CTOAuthor Commented:
Just fixed the issue on my own with the following code.

<script type="text/javascript">
		function check() {
			var element1 = document.getElementsByName("quantity11");
			var element2 = document.getElementsByName("quantity12");
			var element3 = document.getElementsByName("quantityreg");
			
			for (var i=0; i<element1.length; i++) {

				var nmbr1 = parseInt(element1[i].value,10);
				var nmbr2 = parseInt(element2[i].value,10);
				var nmbr3 = parseInt(element3[i].value,10);
				var nmbr = nmbr1 + nmbr2 + nmbr3;
				if (nmbr < 1){
					alert("Please add at least 1 treat pack to your order to proceed.");
					return false;
				}
			}
			
			return true;
		}
	</script>

Open in new window

0
 
Daniel Van Der WerkenIndependent ConsultantCommented:
Fine, but if nbr1 = -5 and nbr2 = 10 and nbr3 = 10, you have a nbr = 15 and you didn't meet your requirements.
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Nathan RileyFounder/CTOAuthor Commented:
Found the solution on my own with trial and error.
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