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Changing the path of a column in a text file using batch

Posted on 2014-03-17
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Last Modified: 2014-03-17
Hi,


I want to replace the first column of the text file with another drive location and strip all the subfolders in between. How can I accomplish this in batch?

"\\myserver\sub1\sub2\abc1.pdf","ABC_018-2002-A_0_20011231_20020215__1.pdf","ABCInc","A"


becomes:

"Z:\process\abc1.pdf","ABC_018-2002-A_0_20011231_20020215__1.pdf","ABCInc","A"
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Question by:LuckyLucks
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1 Comment
 
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Accepted Solution

by:
oBdA earned 500 total points
ID: 39934899
Try this:
@echo off
setlocal
set SourceFile=D:\Temp\test.txt
set TargetFile=D:\Temp\test-new.txt
set NewFolder=Z:\process
if exist "%TargetFile%" del "%TargetFile%"
echo Processing '%SourceFile%' ...
for /f "tokens=1* delims=," %%a in ('type "%SourceFile%"') do (
	>>"%TargetFile%" echo "%NewFolder%\%%~nxa",%%b
)
echo ... done.

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Input and output file location can be passed using the command line or queried for if you prefer that.
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