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REGEX Help for Twitter

Posted on 2014-03-18
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Last Modified: 2014-03-18
Hello guys,

Can you help me with the REGEX for the following?

I want to extract the "username" out of any of the following strings. The main differences are http[s], trailing slash, the inclusion of #!, and a variant that includes some other stuff in the url.

Thank you!

http://twitter.com/username/
http://twitter.com/username

https://twitter.com/username/
https://twitter.com/username

http://twitter.com/#!/username/
https://twitter.com/#!/username/

http://twitter.com/intent/user?screen_name=username
https://twitter.com/intent/user?screen_name=username
0
Comment
Question by:EffinGood
6 Comments
 
LVL 84

Expert Comment

by:ozo
Comment Utility
.*\b(\w+)
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LVL 27

Expert Comment

by:yodercm
Comment Utility
If you are using php, there is an easier way (assuming that you are showing all possible formats).

Just explode() the string on "/", take the 4th part.  It will be either the username or "intent" or "#!".  In the second case, explode again on "=" and the last part will be the username.  In the third case, take the original 5th part.

The php explode() function is awesome.
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Author Comment

by:EffinGood
Comment Utility
Well, the problem is that the strings are located in a big file full of other chars, so I need to examine the entire file to pull these out.

There will be other urls in there - I'm just looking for those with the 'twitter' part.
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Accepted Solution

by:
gr8gonzo earned 500 total points
Comment Utility
I highly recommend installing the free tool "The Regex Coach" - I've been using it for years.

That said, try this on:
<?php

$urls = array(
"http://twitter.com/username/",
"http://twitter.com/username",
"https://twitter.com/username/",
"https://twitter.com/username",
"http://twitter.com/#!/username/",
"https://twitter.com/#!/username/",
"http://twitter.com/intent/user?screen_name=username",
"https://twitter.com/intent/user?screen_name=username");

foreach($urls as $url)
{
  echo "URL: {$url}\n";
  preg_match("@https?://twitter.com/(?:#!/|intent/user\?screen_name=)?(\w+)@",$url,$matches);
  echo "Username: " . $matches[1] . "\n";
}
?>

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You should get this result:
URL: http://twitter.com/username/
Username: username
URL: http://twitter.com/username
Username: username
URL: https://twitter.com/username/
Username: username
URL: https://twitter.com/username
Username: username
URL: http://twitter.com/#!/username/
Username: username
URL: https://twitter.com/#!/username/
Username: username
URL: http://twitter.com/intent/user?screen_name=username
Username: username
URL: https://twitter.com/intent/user?screen_name=username
Username: username

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0
 

Author Closing Comment

by:EffinGood
Comment Utility
Nice! Thank you! I remember that nifty piece of software now - it's been eons! Thank you very much Gonzo!
0
 
LVL 35

Expert Comment

by:Terry Woods
Comment Utility
Very similar to @gr8gonzo's, though I wrote it independently:
preg_match_all("@https?://twitter.com/(?:#!/)?(?:.*\?screen_name=)?((?!intent)\w+)@i", $data, $matches);
print_r($matches[1]);

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