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search partial string from a file and replace with another string using batch script and shell script
Posted on 2014-03-19
Hello Experts,
I need a batch file and a shell script for searching one string and replacing with other in an existing XML file.
Here is my XML file called "ran.xml":
from the above script i have to search for :
<PROPERTY NAME="DBURL">..
then replace it with :
<PROPERTY NAME="DBURL">REP/STORE/CAL
I have to search the initial only and then replace it with final string.
I need a batch file and a shell script for searching one string and replacing with other in an existing XML file.
Here is my XML file called "ran.xml":
<?xml version="1.0"?>
<!DOCTYPE MODULE SYSTEM "file://localhost/SYSTEMi_HOME_UNIX/Systemi/Doc/Module.dtd" [
<!ENTITY license SYSTEM "file://localhost/SYSTEMi_HOME_UNIX/Systemi/keys/CENTNAME_license.xml">
<!ENTITY hostname "CENTHOSTNAME">
]>
<MODULE NAME="ABC in Single Node" INDEX="&index;">
<SYSTEM>
<PROPERTIES>
<!-- Begin Client App/Web Server related Properties -->
<PROPERTY NAME="BC_TIMEOUT">90</PROPERTY>
<!--End DB related items -->
<INSTANCE>
<PROPERTY NAME="DBURL">CDBURL</PROPERTY>
<PROPERTY NAME="DBUSER">CDBUSER</PROPERTY>
</INSTANCE>
<!--Begin Log related items -->
<PROPERTY NAME="LOGFILE">&systemi_root;/Systemi/log/client&node_id;_{0,date,MMM-dd-yy-HH-mm-ss}</PROPERTY>
<PROPERTY NAME="LOG_ENCODING">UTF-8</PROPERTY>
<!--End Log related items -->
</PROPERTIES>
</SYSTEM>
</MODULE>
from the above script i have to search for :
<PROPERTY NAME="DBURL">..
then replace it with :
<PROPERTY NAME="DBURL">REP/STORE/CAL
I have to search the initial only and then replace it with final string.
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4 Comments
Active today
Do you mean a Unix/Linux shell script?
If so, here is a one-liner:
If so, here is a one-liner:
sed -i.bak 's@\(<PROPERTY NAME="DBURL">\).*$@\1REP/STORE/CALL/DBURL</PROPERTY>@' ran.xml
Active 2 days ago
I am getting the below error:
[root@msi-vmappleap1 sloba]# sed -i.bak 's@\(<PROPERTY NAME="DBURL">\).*$@\jdbc:o
sed: -e expression #1, char 54: unknown option to `s'
[root@msi-vmappleap1 sloba]# sed -i.bak 's@\(<PROPERTY NAME="DBURL">\).*$@\jdbc:o
sed: -e expression #1, char 54: unknown option to `s'
Active today
First, your command isn't quite the same as the one suggested.
You're missing the digit "1" on the right hand side between the backslash and "jdbc".
It is important because "\1" refers to the string between parentheses on the left hand side.
The end of the replacement string doesn't seem correct - shouldn't it be "</PROPERTY>" instead of "</PROPERT" ?
Second, I couldn't know that the replacement part would contain "@". I used that character as the delimiter, so the character inside the replacement string must be escaped using a backslash.
Here is a corrected version:
You're missing the digit "1" on the right hand side between the backslash and "jdbc".
It is important because "\1" refers to the string between parentheses on the left hand side.
The end of the replacement string doesn't seem correct - shouldn't it be "</PROPERTY>" instead of "</PROPERT" ?
Second, I couldn't know that the replacement part would contain "@". I used that character as the delimiter, so the character inside the replacement string must be escaped using a backslash.
Here is a corrected version:
sed -i.bak 's@\(<PROPERTY NAME="DBURL">\).*$@\1jdbc:oracle:thin:\@slobadb:1521:db11g</PROPERTY>@' ran.xml
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