search partial string from a file and replace with another string using batch script and shell script

Hello Experts,

I need a batch file and a shell script for searching one string and replacing with other in an existing XML file.

Here is my XML file called "ran.xml":

<?xml version="1.0"?>
<!DOCTYPE MODULE SYSTEM "file://localhost/SYSTEMi_HOME_UNIX/Systemi/Doc/Module.dtd" [
        <!ENTITY license SYSTEM "file://localhost/SYSTEMi_HOME_UNIX/Systemi/keys/CENTNAME_license.xml">
        <!ENTITY hostname "CENTHOSTNAME">
        ]>
 
<MODULE NAME="ABC in Single Node" INDEX="&index;">
    <SYSTEM>
        <PROPERTIES>
            <!-- Begin Client App/Web Server related Properties -->
                
            <PROPERTY NAME="BC_TIMEOUT">90</PROPERTY>
           
            <!--End DB related items -->
            <INSTANCE>
                <PROPERTY NAME="DBURL">CDBURL</PROPERTY>
                <PROPERTY NAME="DBUSER">CDBUSER</PROPERTY>
            </INSTANCE>
 
            <!--Begin Log related items -->
            <PROPERTY NAME="LOGFILE">&systemi_root;/Systemi/log/client&node_id;_{0,date,MMM-dd-yy-HH-mm-ss}</PROPERTY>
            <PROPERTY NAME="LOG_ENCODING">UTF-8</PROPERTY>
            <!--End Log related items -->
                                   
</PROPERTIES>
    </SYSTEM>
</MODULE>

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from the above script i have to search for :
<PROPERTY NAME="DBURL">..

then replace it with :

<PROPERTY NAME="DBURL">REP/STORE/CALL/DBURL</PROPERTY>


I have to search the initial only and then replace it with final string.