Removing path and quotes in batch

Hi

   I am looking to process a txt file that has the following format and get a new text file of the new format, also listed below. In essence, the batch would need to remove all drive and folders and unquote the first entry. Please help me with writing the batch code to do it.

Input file:
"Z:\B\1.pdf","newfile1.pdf",<mystring>,<mystring>

Would like:

1.pdf

Thanks
LuckyLucksAsked:
Who is Participating?
 
Steve KnightIT ConsultancyCommented:
@echo off
(for /f "tokens=1 delims=," %%a in (oldfile.csv) do echo %%~nxa) >newfile.csv

Steve
0
 
Dan CraciunIT ConsultantCommented:
Don't know in batch, in PS you can do it like this:
$inputText = "`"Z:\B\1.pdf`",`"newfile1.pdf`",<mystring>,<mystring>"
$outputText = $inputText.Split("`"")[1] # get only the file name, with path
$outputText = $outputText.Split("\")[-1] # get only the file name
echo $outputText

Open in new window

HTH,
Dan
0
 
Steve KnightIT ConsultancyCommented:
That means take the first part of the line upto the comma in file oldfile.csv and for each entry the ~ strips the quotes, and "nx" leaves the Name and eXtension of the filename only.  Whole lot redirected into one file, or you can do other processing in the loop rather than creating a new file.

Steve
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.