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Replicate folder structure and move files based on Extension

I have thousands of subfolders I need to duplicate in a new location, however, I need to keep the folders structure and any files that aren't being moved in the old location.   I then need to loop through each subfolder and if any of the extensions are matched, then move those files to the same subfolder in the new location.  

Parent Folder - c:\Folder\Data\subfolders
New Folder - d:\ArchiveFolder\ArchiveData\subfolders

Extensions:
.l03, .l04, .l05, .l06, .l07, .l08, .l09, .l10

I'm a powershell newbie, so be gentle.  :)

Thanks,

Jeremy
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Jeremyw
Asked:
Jeremyw
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1 Solution
 
Dan CraciunIT ConsultantCommented:
You can try this:
# recreate structure and move files
# script created for E-E, question Q_28397320

$inputPath = "c:\Folder\Data"
$outputPath = "d:\ArchiveFolder\ArchiveData"

#double up the "\" to use on replace  ("\" must be escaped): result will be c:\\folder\\data\\
$inputPath = $inputPath -replace "\\", "\\"
$inputPath += "\\"

#recreate the folder structure
gci $inputPath -Directory -Recurse | %{

    #remove the original folder from the folder name; that's why the "//"  was needed
    $folderName = $_.FullName -replace $inputPath, ""
    New-Item -ItemType Directory -Path "$outputPath\$folderName"
}

#move the files
gci $inputPath -Include @("*.l03", "*.l04", "*.l05", "*.l06", "*.l07", "*.l08", "*.l09", "*.l10") -Recurse | %{
    $fileName = $_.FullName -replace $inputPath, ""
    Move-Item $_.FullName -Destination "$outputPath\$fileName"
}

Open in new window

HTH,
Dan
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Raheman M. AbdulCommented:
copy -Recurse -Filter *.l03 -Path c:\Folder\Data\Subfolders -Destination d:\ArchiveFolder\ArchiveData -ErrorAction SilentlyContinue


and similarly replace *.l03 with other extensions. I am working on it to include all extensions in one line.
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Dan CraciunIT ConsultantCommented:
@Raheman Mohammed Abdul: it's 5 lines above :)
Use -Include @()

The OP did require a move, though, not just a copy...
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Raheman M. AbdulCommented:
It's late night here in london so thought will work on it tomorrow. We can replace with move instead of copy. Thanks Dan.
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JeremywAuthor Commented:
Dan,

So yours will do the following.  

Take
C:\Folder\Data\Subfolder1
C:\Folder\Data\Subfolder2
etc.

Create the folders in
D:\ArchiveFolder\ArchiveData\Subfolder1
D:\ArchiveFolder\ArchiveData\Subfolder2
etc.

Then move any of the .lxx extension files to the the folder on D: it came from.  

Also need to make sure it keeps the original folder structure on C: as we will be leaving files in those folders.  

What exactly do these lines do?  I'm not really understanding the replace \\

#double up the "\" to use on replace  ("\" must be escaped): result will be c:\\folder\\data\\
$inputPath = $inputPath -replace "\\", "\\"
$inputPath += "\\"

Thanks,

Jeremy
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Dan CraciunIT ConsultantCommented:
I need to get rid of "C:\Folder\Data\" part from the file name, and keep only the "Subfolder1", "Subfolder1\Subfolder2" etc part.

I'm doing that by searching for the string "C:\Folder\Data\" and replacing it with nothing (effectively removing it). The problem is that "\" has a special meaning in Powershell and you need to escape it by doubling it.

My solution does not move the folders. It creates empty folders in the target path, then moves only files. The original structure will remain intact.

There is a chance that empty folders will remain in the source path. Let me know if you want to add to the script so it looks for empty folders and deletes them.
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JeremywAuthor Commented:
Empty folders on either side will be ok.  Just had to make sure the original structure stayed the same since there are other files that will be used.  Will do some tests tomorrow.

Thanks,

Jeremy
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Raheman M. AbdulCommented:
Ignore this please.
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JeremywAuthor Commented:
I apologize for the delay Dan.  After a few tests, this worked exactly as requested.   Thanks so much for your help.
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Dan CraciunIT ConsultantCommented:
Glad I could help!
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