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Limiting rows returned from count of records in a subquery.

Hi Team,

I am trying to nut out a query which returns the COUNT of rows in a history table where a resultcode is 'NOT' and that COUNT is more than 2.

I have been sweeping the Net to find a clue, alas without luck.

EG

Select KEY1,Company, (select COUNT(resultcode) from C1)
from CONTACT1
inner join CONTACT2 on Contact1.ACCOUNTNO = CONTACT2.ACCOUNTNO
where Exists (select key1,COUNT(RESULTCODE)
from CONTACT1 c1
inner join CONTACT2 c2 on C1.ACCOUNTNO = C2.ACCOUNTNO
left join CONTHIST CH on CH.ACCOUNTNO = C1.ACCOUNTNO
where
CH.RESULTCODE = 'SHD'
GROUP BY C1.KEY1)

I get this error "Invalid object name 'C1'"

All help is achknowledged.
Cheers
Bernard

ASKER CERTIFIED SOLUTION

GowthamNatarajan

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Jim Horn

>and that COUNT is more than 2.
To filter on an aggreate you need a HAVING clause, not a WHERE clause.

Select KEY1,Company, (select COUNT(resultcode) from C1)
from CONTACT1 
	inner join CONTACT2 on Contact1.ACCOUNTNO = CONTACT2.ACCOUNTNO
where Exists (
	select key1,COUNT(RESULTCODE)
	from CONTACT1 c1
		inner join CONTACT2 c2 on C1.ACCOUNTNO = C2.ACCOUNTNO
		left join CONTHIST CH on CH.ACCOUNTNO = C1.ACCOUNTNO
		where CH.RESULTCODE = 'SHD'
		GROUP BY C1.KEY1
		HAVING count(resultcode) > 2)   -- < --  Something like this

Open in new window

There's an article out there on SQL Server GROUP BY Solutions; scroll down to #3 'Filter rows by a condition on an aggregate value: HAVING'.

BernardGBailey

ASKER

GowthamNatarajan,

I was able to get this query going from your code after making a change. See under

select T.KEY1,T.Company,T.NOTCnt
from (Select CONTACT1.KEY1,CONTACT1.Company,
(select COUNT(CH.ResultCode) from CONTHIST CH
left join CONTACT2 c2 on c2.ACCOUNTNO = CH.ACCOUNTNO
where CH.Accountno = CONTACT1.AccountNo and CH.resultCode = 'NOT'
and CH.ONDATE > ULASTSALE
and contact1.key5 ='GREEN'
) AS NOTCnt
from CONTACT1
inner join CONTACT2 on CONTACT2.ACCOUNTNO = CONTACT1.ACCOUNTNO) T where T.NOTCnt > 2

Many thanks

Jim, Sorry I had no luck making your solution work.