asked on

sql query to create new records from 0001 to 9999

As the title suggests, i need to create a new table call CardPool

In this table i need the following structure

CardNumber (4 digits unique number) clustered
ActiveStatus (bit) default 0

then in the table i need to have the rows from 0001 to 9999
i,e,
0001
0002
0003
...
9998
9999

Does anyone know the correct script to generate this?

Guy Hengel [angelIII / a3]

there are other ways to do ...

;with data as (select 1 n union all select n + 1 from data where n < 9999 )
select right('000' + cast(n as varchar(10)), 4) from data
option (maxrecursion 10000)

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;with digits as (select '0' n 
union all select '1'
union all select '2'
union all select '3'
union all select '4'
union all select '5'
union all select '6'
union all select '7'
union all select '8'
union all select '9'
)
select d1.n + d2.n + d3.n + d4.n
 from digits d1, digits d2, digits d3, digits d4
where d1.n + d2.n + d3.n + d4.n <> '0000'
order by 1

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Guy Hengel [angelIII / a3]

of course, the above is only the SELECT part, which you can use to actually INSERT into your table

websss

ASKER

Thanks,
I'm not sure how this works as i cannot see inserting into the CardNumber column?

Guy Hengel [angelIII / a3]

the syntax, from above, would be in general:
;WITH alias AS ( <some query> )
INSERT INTO yourtable ( <columns> )
SELECT <columns>
FROM alias

so, taking my first query sample:

;with data as (select 1 n union all select n + 1 from data where n < 9999 )
INSERT INTO CardPool ( CardNumber ) 
select right('000' + cast(n as varchar(10)), 4) 
from data
option (maxrecursion 10000)

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Scott Pletcher

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