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using reflection , or any means, how can I get the name of a source code file at runtime?

using reflection ,or any means, how can I get the name of a source code  file at runtime?
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HLRosenberger
Asked:
HLRosenberger
3 Solutions
 
käµfm³d 👽Commented:
What version of .NET and/or Visual Studio are you using?
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Carl TawnSystems and Integration DeveloperCommented:
Which source code file? The one from which the executing method comes, or something else?

You can get the source file of the executing method using:
System.Diagnostics.StackTrace stack = new System.Diagnostics.StackTrace(true);
string executingFile = stack.GetFrame(0).GetFileName();

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Jacques Bourgeois (James Burger)PresidentCommented:
For this to work, you need to make sure that you "Generate debug info" in the Advanced Compile Options (Compile tab of the project's Properties window) and that you distribute the .pdb file that is generated along with the application.
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Alan WarrenCommented:
Hi HLRosenberger,

I use the following to determine exact source of error using system.reflection.methodbase()
      Try
        ' ...

      Catch ex As Exception
        Dim sf As System.Diagnostics.StackFrame = New System.Diagnostics.StackFrame()
        Dim mb As System.Reflection.MethodBase = sf.GetMethod()
        Session("ErrorMessage") = "Error in " _
          & Context.Request.Url.ToString().Replace(Context.Request.Url.GetLeftPart(UriPartial.Authority) & VirtualPathUtility.ToAbsolute("~/"), "~/") _
          & "." & mb.Name _
          & "<br />" & ex.Message _
          & "<br />" & ex.Source
      End Try

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Respectfully yours,
Alan
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HLRosenbergerAuthor Commented:
thanks
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käµfm³d 👽Commented:
I see my question was completely ignored. I asked it for a reason. If you're working under .NET 4.5, then you might investigate The CallerFilePathAttribute class.
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