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PHP - Get the dominant color of any image

Posted on 2014-04-03
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Last Modified: 2014-04-04
Hi E's, I tried to find a script that get the dominant color of image, and I found the below code. Lots of websites show that code, so I guess, was good:
<?
    $i = imagecreatefromjpeg("imagem.jpg");
     
    for ($x=0;$x<imagesx($i);$x++) {
    for ($y=0;$y<imagesy($i);$y++) {
    $rgb = imagecolorat($i,$x,$y);
    $r = ($rgb >> 16) & 0xFF;
    $g = ($rgb >> & 0xFF;
    $b = $rgb & 0xFF;
     
    $rTotal += $r;
    $gTotal += $g;
    $bTotal += $b;
    $total++;
    }
    }
     
    $rAverage = round($rTotal/$total);
    $gAverage = round($gTotal/$total);
    $bAverage = round($bTotal/$total);

echo "$rAverage";
?>

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The problem is this error:
Parse error: syntax error, unexpected '&' in /home/pedro/public_html/biblioteca/tutoriais/1267/processa.php on line 8

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Line 8 is this one:
$g = ($rgb >> & 0xFF;

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Can you please tell me how do I put this script to work?

The best regards, JC
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Question by:Pedro Chagas
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1 Comment
 
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Accepted Solution

by:
Dan Craciun earned 2000 total points
ID: 39977130
You did not copy the whole line. It used to say:
$g = ($rgb >> 8) & 0xFF;

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HTH,
Dan
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