create a file object without a path

I have a project that works fine with some code like this -
FileInputStream fileIn = new FileInputStream(new File("c:\path\filename.xls"));
As long as I'm on my local system. However, there is a need for others to use the same project. so I'm wondering how I can embed the filename.xls file into the class and create a new file (of FileInputStream) object without having to refer to the drive or path. Assume the class is named generator and the filename.xls is in the src folder.
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awking00Asked:
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CEHJCommented:
Well, assuming you can write to the current directory, why not just use the file name only?
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awking00Author Commented:
I meant ... (or FileInputStream)
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Peter_TorettoCommented:
Hi,

Try using code similar to this: -
 
File file = new File("C:\\user\\Desktop\\dir1\\dir2\\filename.txt");
file.getParentFile().mkdirs();
FileWriter writer = new FileWriter(file);

Just use the file name.

Hope you find this information useful.

Regards
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CEHJCommented:
I wasn't thinking. In order to solve the problem i mentioned, as well as yours, you should probably use the user's home directory

File f = new File(System.getProperty("user.home"), saveAsFilename); // ('saveAsFilename' is of course a String)

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That should always work, and cross platform
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awking00Author Commented:
CEHJ,
The problem here is that "user.home" seems to identify a path that is on a local drive and what I want is for it to identify the file from the class itself. Adding the fact that the package name is org.assn.generator, could I define the path as something like -
org.assn.generator. (or /) filename.xls? If so, are quotes needed anywhere?
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CEHJCommented:
seems to identify a path that is on a local drive
Yes. Questions:

a. Do you want to write to the file?
If yes, then
b. Why is that a problem?
c. Where else could/should it be?
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awking00Author Commented:
The file is static and will only be read from. I don't want to have multiple persons keeping a copy of the file on their local drives, but maintain the file within the class.
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CEHJCommented:
but maintain the file within the class.
You should load it as a resource from the app's jar

Better to load your files/images as resources:
http://technojeeves.com/index.php/aliasjava1/78-loading-files-as-resources-in-java-with-netbeans
http://technojeeves.com/index.php/aliasjava1/80-loading-files-as-resources-in-java-with-eclipse
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awking00Author Commented:
Perhaps I asked this question in too complex a fashion. I resolved the issue simply by copying the file to the root directory of the project then was able to use -
File file = new File("filename.xls") => without any reference to path, which is what I wanted
Then simply create the FileInputStream as new FileInputStream(file). I'm not sure how I should handle the points since I did sort of figured it out on my own but, as an EE regular, I feel uncomfortable not giving points. Any input in this regard is most welcome. Thanks to everyone for their efforts.
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CEHJCommented:
 I resolved the issue simply by copying the file to the root directory of the project then was able to use - File file = new File("filename.xls") => without any reference to path, which is what I wanted
So, IOW you did exactly what i suggested in my first comment HERE ;)

The problem is that 'filename.xls' doesn't mean 'use the root of the project directory', it means 'use the current directory'. Depending on how the app is run, that could mean that it's not found. That would not be the case with my later suggestion after discovering that it's read-only.

http://technojeeves.com/index.php/aliasjava1/91-find-the-current-directory-in-java
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awking00Author Commented:
Sorry, I overlooked this earlier response entirely.
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CEHJCommented:
:)
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