I would guess there's some rounding taking place on the site you've linked to. The same site measures the distance as 9 feet which is about 2.75 meters. Are you sure your coordinates are accurate?

//::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::://::: ::://::: This routine calculates the distance between two points (given the ::://::: latitude/longitude of those points). It is being used to calculate ::://::: the distance between two locations using GeoDataSource (TM) prodducts ::://::: ::://::: Definitions: ::://::: South latitudes are negative, east longitudes are positive ::://::: ::://::: Passed to function: ::://::: lat1, lon1 = Latitude and Longitude of point 1 (in decimal degrees) ::://::: lat2, lon2 = Latitude and Longitude of point 2 (in decimal degrees) ::://::: unit = the unit you desire for results ::://::: where: 'M' is statute miles ::://::: 'K' is kilometers (default) ::://::: 'N' is nautical miles ::://::: ::://::: Worldwide cities and other features databases with latitude longitude ::://::: are available at http://www.geodatasource.com ::://::: ::://::: For enquiries, please contact sales@geodatasource.com ::://::: ::://::: Official Web site: http://www.geodatasource.com ::://::: ::://::: GeoDataSource.com (C) All Rights Reserved 2014 ::://::: ::://:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::function distance(lat1, lon1, lat2, lon2, unit) { var radlat1 = Math.PI * lat1/180 var radlat2 = Math.PI * lat2/180 var radlon1 = Math.PI * lon1/180 var radlon2 = Math.PI * lon2/180 var theta = lon1-lon2 var radtheta = Math.PI * theta/180 var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta); dist = Math.acos(dist) dist = dist * 180/Math.PI dist = dist * 60 * 1.1515 if (unit=="K") { dist = dist * 1.609344 } if (unit=="N") { dist = dist * 0.8684 } return dist} /*53.1330940 -1.1843660TO53.1331060 -1.1843260*/var lat1=53.1330940;var lon1=-1.1843660;var lat2=53.1331060;var lon2=-1.1843260;var kilometers=distance(lat1, lon1, lat2, lon2, 'k'); meters = kilometers*1000alert(meters);

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!