Accurate distance between two GPS coordinates

Hi,

I am having trouble getting an accurate distance between two lat/lon coordinates.  This site, give the correct result which is 2 meters.

http://boulter.com/gps/distance/?from=53.1330940+-1.1843660&to=53.1331060+-1.1843260&units=k

Here is the code I am using :
function distance(lat1, lon1, lat2, lon2, 'K') {
	var radlat1 = Math.PI * lat1/180
	var radlat2 = Math.PI * lat2/180
	var radlon1 = Math.PI * lon1/180
	var radlon2 = Math.PI * lon2/180
	var theta = lon1-lon2
	var radtheta = Math.PI * theta/180
	var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
	dist = Math.acos(dist)
	dist = dist * 180/Math.PI
	dist = dist * 60 * 1.1515
	if (unit=="K") { dist = dist * 1.609344 }
	if (unit=="N") { dist = dist * 0.8684 }
	return dist
}  

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This return 2.98 meters as do a lot of other online versions of this calculation. the correct distance is actually 2 meters. Am I missing something?

My coords are :

FROM
53.1330940 -1.1843660
TO
53.1331060 -1.1843260

ANy help appreciated!
Thanks
jellydealAsked:
Who is Participating?
 
Scott Fell, EE MVEConnect With a Mentor Developer & EE ModeratorCommented:
That site is just rounding.   I have code below that comes up with 1.8.  Maybe I have the points off?

http://jsbin.com/vumikayi/1/edit

//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
//:::                                                                         :::
//:::  This routine calculates the distance between two points (given the     :::
//:::  latitude/longitude of those points). It is being used to calculate     :::
//:::  the distance between two locations using GeoDataSource (TM) prodducts  :::
//:::                                                                         :::
//:::  Definitions:                                                           :::
//:::    South latitudes are negative, east longitudes are positive           :::
//:::                                                                         :::
//:::  Passed to function:                                                    :::
//:::    lat1, lon1 = Latitude and Longitude of point 1 (in decimal degrees)  :::
//:::    lat2, lon2 = Latitude and Longitude of point 2 (in decimal degrees)  :::
//:::    unit = the unit you desire for results                               :::
//:::           where: 'M' is statute miles                                   :::
//:::                  'K' is kilometers (default)                            :::
//:::                  'N' is nautical miles                                  :::
//:::                                                                         :::
//:::  Worldwide cities and other features databases with latitude longitude  :::
//:::  are available at http://www.geodatasource.com                          :::
//:::                                                                         :::
//:::  For enquiries, please contact sales@geodatasource.com                  :::
//:::                                                                         :::
//:::  Official Web site: http://www.geodatasource.com                        :::
//:::                                                                         :::
//:::               GeoDataSource.com (C) All Rights Reserved 2014            :::
//:::                                                                         :::
//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::

function distance(lat1, lon1, lat2, lon2, unit) {
	var radlat1 = Math.PI * lat1/180
	var radlat2 = Math.PI * lat2/180
	var radlon1 = Math.PI * lon1/180
	var radlon2 = Math.PI * lon2/180
	var theta = lon1-lon2
	var radtheta = Math.PI * theta/180
	var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
	dist = Math.acos(dist)
	dist = dist * 180/Math.PI
	dist = dist * 60 * 1.1515
	if (unit=="K") { dist = dist * 1.609344 }
	if (unit=="N") { dist = dist * 0.8684 }
	return dist
}       
/*
53.1330940 -1.1843660
TO
53.1331060 -1.1843260
*/
var lat1=53.1330940;
var lon1=-1.1843660;
 
var lat2=53.1331060;
var lon2=-1.1843260;

var kilometers=distance(lat1, lon1, lat2, lon2, 'k'); 
meters = kilometers*1000
alert(meters);

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0
 
Kim WalkerConnect With a Mentor Web Programmer/TechnicianCommented:
I would guess there's some rounding taking place on the site you've linked to. The same site measures the distance as 9 feet which is about 2.75 meters. Are you sure your coordinates are accurate?
0
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