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What's the informix SQL for end of month?

Posted on 2014-04-07

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Last Modified: 2014-10-22

Hi All

I'm butchering my way through creating my first Informix procedure (SQL expert, Informix N00b) and I'm passing a year and month as integers.

Question: Given year and month number, what's the function for automagically determining the last day of that year-month? For example, year=2010 and month=9 should return the date 2010-09-30. Should go in line 17 of the below code block.

Thanks.
Jim

CREATE PROCEDURE informix.sales_distribution(iYear int, iMonth int, iWeekNumber int)

define dtStart DATETIME YEAR TO DAY;
define dtEnd DATETIME YEAR TO DAY;

if iWeekNumber = 1 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-01") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07")
elseif iWeekNumber = 2 then 
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-08") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-14")
elseif iWeekNumber = 3 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-15") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-21")
elseif iWeekNumber = 4 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-22") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07")   -- ????
end if;

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Question by:Jim Horn

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5 Comments

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Accepted Solution

by:Dulton

Dulton earned 2000 total points

ID: 399838352014-04-07

wrap what you're assigning dtEnd on line 17 in LAST_DAY(), it takes a date or datetime argument.

CREATE PROCEDURE informix.sales_distribution(iYear int, iMonth int, iWeekNumber int)

define dtStart DATETIME YEAR TO DAY;
define dtEnd DATETIME YEAR TO DAY;

if iWeekNumber = 1 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-01") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07")
elseif iWeekNumber = 2 then 
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-08") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-14")
elseif iWeekNumber = 3 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-15") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-21")
elseif iWeekNumber = 4 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-22") 

   let dtEnd = LAST_DAY(to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07"))
end if;

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http://pic.dhe.ibm.com/infocenter/idshelp/v115/index.jsp?topic=%2Fcom.ibm.sqls.doc%2Fids_sqs_1538.htm

LVL 66

Author Comment

by:Jim Horn

ID: 399838652014-04-07

... looking ...

LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]

ID: 403967592014-10-22

I've requested that this question be closed as follows:

Accepted answer: 500 points for Dulton's comment #a39983835

for the following reason:

This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.

LVL 66

Author Closing Comment

by:Jim Horn

ID: 403967602014-10-22

I moved on to a different gig and can't verify this, but I suspect this is the correct answer. Thanks.

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