Improve company productivity with a Business Account.Sign Up

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 706
  • Last Modified:

What's the informix SQL for end of month?

Hi All

I'm butchering my way through creating my first Informix procedure (SQL expert, Informix N00b) and I'm passing a year and month as integers.

Question:  Given year and month number, what's the function for automagically determining the last day of that year-month?  For example, year=2010 and month=9 should return the date 2010-09-30.  Should go in line 17 of the below code block.

Thanks.
Jim

CREATE PROCEDURE informix.sales_distribution(iYear int, iMonth int, iWeekNumber int)

define dtStart DATETIME YEAR TO DAY;
define dtEnd DATETIME YEAR TO DAY;

if iWeekNumber = 1 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-01") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07")
elseif iWeekNumber = 2 then 
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-08") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-14")
elseif iWeekNumber = 3 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-15") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-21")
elseif iWeekNumber = 4 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-22") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07")   -- ????
end if;

Open in new window

0
Jim Horn
Asked:
Jim Horn
  • 2
1 Solution
 
DultonCommented:
wrap what you're assigning dtEnd on line 17 in LAST_DAY(), it takes a date or datetime argument.

CREATE PROCEDURE informix.sales_distribution(iYear int, iMonth int, iWeekNumber int)

define dtStart DATETIME YEAR TO DAY;
define dtEnd DATETIME YEAR TO DAY;

if iWeekNumber = 1 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-01") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07")
elseif iWeekNumber = 2 then 
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-08") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-14")
elseif iWeekNumber = 3 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-15") 
   let dtEnd = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-21")
elseif iWeekNumber = 4 then
   let dtStart = to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-22") 

   let dtEnd = LAST_DAY(to_date(to_char(iYear) || "-" || to_char(iMonth) + || "-07"))
end if; 

Open in new window


http://pic.dhe.ibm.com/infocenter/idshelp/v115/index.jsp?topic=%2Fcom.ibm.sqls.doc%2Fids_sqs_1538.htm
0
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorAuthor Commented:
... looking ...
0
 
Guy Hengel [angelIII / a3]Billing EngineerCommented:
I've requested that this question be closed as follows:

Accepted answer: 500 points for Dulton's comment #a39983835

for the following reason:

This question has been classified as abandoned and is closed as part of the Cleanup Program. See the recommendation for more details.
0
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorAuthor Commented:
I moved on to a different gig and can't verify this, but I suspect this is the correct answer.  Thanks.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

Improve Your Query Performance Tuning

In this FREE six-day email course, you'll learn from Janis Griffin, Database Performance Evangelist. She'll teach 12 steps that you can use to optimize your queries as much as possible and see measurable results in your work. Get started today!

  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now