Solved

Crystal Reports VB6 Logon

Posted on 2014-04-07
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1,161 Views
Last Modified: 2014-04-08
Hello Experts,

I am trying to run a Crystal Report thorugh VB6. Here is my code:

Dim crxApp As CRAXDRT.Application
Dim crxRpt As CRAXDRT.Report


    Set crxApp = New CRAXDRT.Application
    Set crxRpt = crxApp.OpenReport(App.Path & "\Reports\DetailRecpt.rpt")
    crxRpt.ParameterFields(1).AddCurrentValue ("44444") 'testing with trans# 44444


CRViewer.ReportSource = crxRpt
CRViewer.ViewReport

Open in new window


It generates this error:

---------------------------
Crystal Report Viewer
---------------------------
Logon failed.
Details: 28000:[Sybase][ODBC Driver][SQL Anywhere]Invalid user ID or password [Database Vendor Code: -103 ]
---------------------------
OK  
---------------------------


I don't have any login info within my VB code as you can see. I cant seem to figure out the syntax for the connection string. I have successfully used this connection string in the past to connect.

"Driver={SQL Anywhere 10};Password=password;Persist Security Info=True;User ID=user;Data Source=sqlbase;Location=sqlbase"


Any help would be appreciated.
0
Comment
Question by:triphen
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8 Comments
 
LVL 101

Accepted Solution

by:
mlmcc earned 500 total points
ID: 39984245
Have you tried using the code you say solved your other issue along the same lines?

http://www.experts-exchange.com/Programming/Languages/Visual_Basic/Q_28404831.html

mlmcc
0
 

Author Comment

by:triphen
ID: 39984431
m1mcc,

Thanks for your response. The solution I accepted there worked but when I moved the EXE out of my development environment it not generates that logon error. I am sure it's because I dont have any connection string in my code, however I dont know the syntax :/
0
 
LVL 101

Assisted Solution

by:mlmcc
mlmcc earned 500 total points
ID: 39984554
There is code provided in the other question that should work.  Crystal doesn't use a connection string as such.  

The code is here

http://www.experts-exchange.com/Programming/Languages/Visual_Basic/Q_28404831.html#a39977258

mlmcc
0
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Author Comment

by:triphen
ID: 39984569
Private Sub SetReportLocation(ByRef RepObj As CRAXDRT.Report)

    Dim CrxDDF As CRAXDRT.DatabaseTable
    Dim CP As CRAXDRT.ConnectionProperties

    For Each CrxDDF In RepObj.Database.Tables
        Set CP = CrxDDF.ConnectionProperties
        CP.DeleteAll
        CP.Add "Connection String", "Driver={SQL Anywhere 10};Password=password;Persist Security Info=True;User ID=user;Data Source=sqlbase;Location=sqlbase"
    Next

    Set CrxDDF = Nothing
    Set CP = Nothing

End Sub




Private Sub Form_Load()

Dim crxApp As CRAXDRT.Application
Dim crxRpt As CRAXDRT.Report

 SetReportLocation crxRpt


    Set crxApp = New CRAXDRT.Application
    Set crxRpt = crxApp.OpenReport(App.Path & "\Reports\DetailRecpt.rpt")
    crxRpt.ParameterFields(1).AddCurrentValue ("44444") 'testing with trans# 44444


CRViewer.ReportSource = crxRpt
CRViewer.ViewReport


End Sub

Open in new window



Generates:

RunTime error 91

Object variable or With Block variable not set
0
 
LVL 101

Assisted Solution

by:mlmcc
mlmcc earned 500 total points
ID: 39984678
This line

SetReportLocation crxRpt

has to come after you instantiate the report obect

after this line

Set crxRpt = crxApp.OpenReport(App.Path & "\Reports\DetailRecpt.rpt")


mlmcc
0
 

Author Comment

by:triphen
ID: 39984685
Looks better, different error

---------------------------
Crystal Report Viewer
---------------------------
Logon failed.
Details: 28000:[Sybase][ODBC Driver][SQL Anywhere]Login mode 'Integrated' not permitted by login_mode setting [Database Vendor Code: -1074 ]
---------------------------
OK  
---------------------------
0
 
LVL 101

Assisted Solution

by:mlmcc
mlmcc earned 500 total points
ID: 39984940
That means the connection string is wrong.  You have it set for Integrated Security and the reort probably isn't or the other ay round

mlmcc
0
 

Author Comment

by:triphen
ID: 39985284
CP.Add "ConnectionString", "Driver={SQL Anywhere 10};Uid=user;Pwd=password;DSN=sqlbase;"

This worked!
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