I am developing a very simple C# Windows Application (it only displays a message box saying "UACtest") that I want it to run at startup without prompting UAC.
For that I created a registry key for it under HKCU, and in the machine that I compiled it (Windows 8 64-bit using Visual Studio 2013) it runs at startup without promping UAC, as expected.
However, if I run the executable on a Windows 7 machine and do exactly the same thing, a UAC prompt is shown at startup.
Please note that the manifest of the executable has "asInvoker" on the "requestedExecutionLevel", the whole manifest is this:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<assembly xmlns="urn:schemas-microsoft-com:asm.v1" manifestVersion="1.0">
<assemblyIdentity version="18.104.22.168" name="MyApplication.app"/>
<requestedExecutionLevel level="asInvoker" uiAccess="false"/>
Also when I directly double click the executable, it never prompts UAC neither on Windows 7 32-bit or in the Windows 8 64-bit, the UAC prompting problem is only at startup.
I also tried to compile the executable on the Windows 7 32-bit machine (to maybe bypass some compatibility issues) and a strange thing happened, in that machine now UAC is not prompted at startup as expected, however, when I make the test on another machine (Windows 7 64-bit under Virtual Box) it prompted UAC at startup.
This has now really puzzled me, can someone please tell me a way to compile it so that it never prompts UAC at startup on all versions of Windows?
The project properties I used on Visual Studio 2013 are the default ones, except: *Target framework: 2.0 *Platform target: x86
And the UAC settings on all machines where the default one: "Notify me only when applications try to make changes on my computer (default)"
Also the name of the executable does not contain words like "install" or "update" to not trigger UAC installer heuristics.