C++ Bitwise

Posted on 2014-04-11
Last Modified: 2014-04-12
I have an array of Char and I am trying to output the bits. I am a little confused on the concepts of mask and shift (looking for a good article to understand these?)

Not sure if either option 1 or option 2 are correct

  for (int x = 0; i < a.arraySize; x++)
         int test1 = sizeof( char );
   const int SHIFT = 8 * sizeof( char ) - 1;
   const unsigned MASK = 1 << SHIFT;

   os << setw( 10 ) <<  " start =  " << a.barray[x] << " = ";
   char test = a.barray[x];
    unsigned test2 = a.barray[x];
         // display bits
         for ( unsigned j = 1; j <= SHIFT + 1; j++ )
               // Option 1
              //  os << ( a.barray[j] & MASK ? '1' : '0' );
            //  a.barray[j] <<= 1; // shift value left by 1
                Option 2
              os << ( test2 & MASK ? '1' : '0' );
              test2 <<= 1; // shift value left by 1
              if ( j % 8 == 0 ) // output a space after 8 bits
                   os << ' ';
         } // end for
   } // end for
Question by:pcomb
LVL 45

Expert Comment

by:Kent Olsen
ID: 39993927
Hi pcomb,

You seem to have the right idea.  :)  A small suggestion though is to leave the data "as is" and shift the mask.

Assume that the char variable contains an 'A'.  The numeric value of the 'A' is 65 decimal, 41 hex, 101 octal, and 100001 binary.  The looping that you're writing should display the binary value, showing the bits from left to right.

The inner loop should probably have look similar to this:

unsigned char Value = 'A';
unsigned char Mask;

for  (Mask = 0x80; Mask; Mask >>= 1)
  os << (Value & Mask) ? '1' : '0';

Open in new window

You can wrap this tight loop with the controls to process the entire array, too.

Good Luck,
LVL 16

Accepted Solution

HooKooDooKu earned 500 total points
ID: 39994062
I am a little confused on the concepts of mask and shift (looking for a good article to understand these?)
Have you tried Wikipedia?

Bit masking and shifting should be easy to understand IF you first understand the idea of big endian and little endian.  But that's only for how multiple bytes are joined to for integer values greater than 255.

In the case of a char, you're talking about only 8 bits, and they are always logically arranged like this:
00000000 = Zero
00000001 = One
00000010 = Two
00000100 = Four
00001000 = Eight
00010000 = Sixteen
00100000 = Thirty-two
01000000 = Sixty-four
10000000 = One-hundred-twenty-eight

You simply add those together for any other value between 0 and 255.  So as a simple example, Five is 00000100 + 00000001.

But shifting is simply moving the digits to the left or right.  So if you start with say Two and shift to the left (<<) two places you start with
00000010 <<  and you wind up with
00001000 because the 1's are shifted to the left.

Bit Masking is how you determine if a particular bit is turned on or off by taking the value in question and doing a logical AND against a mask.  So if you want to know if a particular value has the 7th bit (i.e. the bit representing a value of Two) turned on, you simply AND the value in question with 00000010.

So the value for Sixty-six is 01000010.  Is the 7th bit turned on?
01000010 - value in question
00000010 - Mask for the 7th bit
======== - AND the bits together
Since the result is equal to the Mask, then the 7th bit is turned on.

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