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ComboBoxes accepting the same values?

I have 2 combobox controls that are loaded via a DataTable. Both CB's use the same DataTable to load them. However, prior to loading I assign the DataTable to a newly created DataTable. I'm loading these CB's with the same values, however, each one could contain a different selected value.

My problem is that when I select a value from one, the other CB automatically reflects the same value, why is that and how can that be resolved...other than creating a new routine as a separate load.

Here is my code:

    Public Sub LoadCombo_Direction()
            Dim ds As New DataSet


            cmbDirection1.DataSource = Nothing
            cmbDirection2.DataSource = Nothing

            If EH.DataSet.Tables(0).Rows.Count > 0 Then
                ds = EH.DataSet

                RemoveHandler cmbDirection1.SelectedIndexChanged, AddressOf cmbDirection1_SelectedIndexChanged
                cmbDirection1.DisplayMember = EH.DataSet.Tables(0).Columns(1).ColumnName
                cmbDirection1.ValueMember = EH.DataSet.Tables(0).Columns(0).ColumnName
                cmbDirection1.DataSource = EH.DataSet.Tables(0)
                cmbDirection1.SelectedIndex = -1

                cmbDirection2.DisplayMember = ds.Tables(0).Columns(1).ColumnName
                cmbDirection2.ValueMember = ds.Tables(0).Columns(0).ColumnName
                cmbDirection2.DataSource = ds.Tables(0)
                cmbDirection2.SelectedIndex = -1
                AddHandler cmbDirection1.SelectedIndexChanged, AddressOf cmbDirection1_SelectedIndexChanged
            End If

        Catch ex As Exception
            EH.ErrorMessage = "LoadCombo_Direction() - " & ex.Message & "~E"
        End Try

        EH.ProcessMessages(Me, sbr, EH.ErrorMessage)
    End Sub

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1 Solution
Change this line

ds = EH.DataSet


ds = EH.DataSet.Copy()
BlakeMcKennaAuthor Commented:
That worked CodeCruiser but what essentially was happening with the way I was doing it?
You were just copying the reference of the same dataset into the new variable(so 2 variables pointing to the same object in memory) instead of creating a real copy of it.
BlakeMcKennaAuthor Commented:
Got it...thanks for the clarification!
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