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move sequential files into folders

Posted on 2014-04-12
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Last Modified: 2014-04-13
Is there a quick way to move a large number of files into sub-folders? I have a directory filled with a larger number of files (tens of thousands). I would like to move them into sub-directories, evenly, and in order. I could use a round robin sort of shuffle, but that would not keep them in order.

For example, if there were only 100 files total folder "1" would have files 1-10, folder "2" would have 11-20, etc. It is important that the folders have as close to even counts as possible. And, I don't always know how many files I will be dealing with.

Is this a fairly easy one liner type of fix, or is this a more detailed script type problem. I am hoping someone knows how to dole them out, assuming that the directories (1-10) are already created.

Any thoughts?
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Question by:stakor
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A-p-u earned 500 total points
ID: 39996926
Puts an equal number of files in each destination directory. If the number of files doesn't go into the number of destination directories evenly, any extra files are left in the source directory.

#!/usr/bin/perl

###########################################################################

$sourcedirectory = '/path/to/source/files';
$destinationdirectory = '/path/to/destination/directories';
$numdestdirectories = 10;  # number of destination directories, named 1 to $numdestdirectories

###########################################################################

my $numfiles = files_in_dir($sourcedirectory);
my @listfiles = sort(files_in_dir($sourcedirectory));

my $filesperdir = int($numfiles / $numdestdirectories);
print "Number of files in $sourcedirectory: $numfiles\n";
print "Number of files in each destination: $filesperdir\n";

my $nextdir = 1;
while ($nextdir <= $numdestdirectories)
{
  my $count = 0;
  while ($count < $filesperdir)
  {
    my $filenum =
	$count + ($nextdir * $filesperdir) - $filesperdir;
    rename "$sourcedirectory/$listfiles[$filenum]",
	"$destinationdirectory/$nextdir/$listfiles[$filenum]";
    $count++;
    if ($count == $filesperdir) { $nextdir++; }
  }
}

###########################################################################

sub files_in_dir
{
  # Source: http://www.perlmonks.org/?node_id=606862
  my $dir = $_[0];
  opendir my $dh, $dir or die "opendir '$dir' - $!";
  grep { -f } readdir $dh;
}

###########################################################################

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