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  • Status: Solved
  • Priority: Medium
  • Security: Public
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Check resource room calendar for corruption

Environment

Exchange 2010 SP1

Email client : outlook 2010

I got request to check on resource room calender for corruption as it is slow.

I understand there might be different reasons behind slowness but i just want to check if there is quick way to check for corruption to fix slow response.
0
itadminhelp
Asked:
itadminhelp
  • 2
1 Solution
 
aces4all00Commented:
Try the following from the Exchange Management Shell replacing user@yourdomain.com  with the primary SMTP address of the mailbox in question

New-MailboxRepairRequest -Mailbox user@yourdomain.com -CorruptionType SearchFolder,AggregateCounts,ProvisionedFolder,FolderView -DetectOnly $True

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Results and progress are written to the event log.  Look for event IDs 10047 - 10064 under the MSExchangeIS Mailbox Store source.

Run the command without the "-DetectOnly $True" option to also try to repair issues.

See http://blogs.technet.com/b/exchange/archive/2010/08/23/3410708.aspx for more information or run
help New-MailboxRepairRequest -FullDetails

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for more info.
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itadminhelpAuthor Commented:
Thanks Peter,

I am new to  Powershell.

I opened up Exchange Management Shell with Admin access on my exchange server.

Ran


New-MailboxRepairRequest -Mailbox user@yourdomain.com -CorruptionType SearchFolder,AggregateCounts,ProvisionedFolder,FolderView -DetectOnly $True

Note: i changed user@yourdomain.com to my email addresss

I got error as below with red fonts.
A positional parameter cannot be found that accepts argument 'True'.
    + CategoryInfo          : InvalidArgument: (:) [New-MailboxRepairRequest], ParameterBindingException
    + FullyQualifiedErrorId : PositionalParameterNotFound,New-MailboxRepairRequest

Do you know what i am doing wrong?

Thanks,
0
 
aces4all00Commented:
That was my error.  Remove $True and it should go through ok.  It should have read:
New-MailboxRepairRequest -Mailbox user@yourdomain.com -CorruptionType SearchFolder,AggregateCounts,ProvisionedFolder,FolderView -DetectOnly

Open in new window

0

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