Pass values from gridview button control to another page

I have a gridview in a page with three button controls in template fields. The gridview shows several different summary totals. For each button, on button click I want to open a 'popup' window that displays a details gridview for that row.  (The values I need to pass to the details gridview are columns 1 and 2. (lockbox and credit date).

Can someone help me with this?  I've seen examples for using a hyperlink button control but I'm using a regular button control.  Also, if I click the button within in a certain row does it make that row the 'selected row'?

Any help would be greatly appreciated.

Thanks.
imstac73Asked:
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Easwaran ParamasivamConnect With a Mentor Commented:
Define the column in client side:

Client side:

<asp:TemplateField HeaderText="Popup" ShowHeader="False">
  <ItemTemplate>
    <asp:LinkButton ID="Popup" runat="server" CausesValidation="false" Text="Popup" CommandArgument='<%# eval("YourRowIDColumn") %>' oncommand="btnPopup_Command" />
   </ItemTemplate>
</asp:TemplateField>

Open in new window


Server side:

Protected Sub btnPopup_Command(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.CommandEventArgs)

   Dim myId As Integer = e.CommandArgument

---   Your changes goes here to popup another window using the id

Open in new window

End Sub
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imstac73Author Commented:
Thanks EaswaranP

So I have two column values that I need to pass to the new window; how do I add the additional one to the 'eval' code?
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imstac73Author Commented:
I figured it out...thanks so much for your help!
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