Solved

How to define XSD conditionally depending on another element?

Posted on 2014-04-16
5
509 Views
Last Modified: 2014-06-01
Hi,
How to define my XSD, if the value of <Action> element is 'Update', <UpdateReason> element should NOT be blank.

possible values of <Action> tag are New / Update / Delete. In case of 'Update' , <UpdateReason> should NOT be blank.

Can anyone help me please?
0
Comment
Question by:GouthamAnand
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
5 Comments
 
LVL 60

Accepted Solution

by:
Geert Bormans earned 500 total points
ID: 40005231
That is a co-occurence constraint.

That can not be modelled in XSD1.0
If you need to use XSD1.0, then you need to embed schematron rules
most parsers support schematron embedding one way or another

XSD1.1 has assertions,
If you parser supports XSD1.1 you can use assertions
Can you verify XSD1.1 support?
0
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 40005321
Here is an example XSD1.1

<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified"
    xmlns:vc="http://www.w3.org/2007/XMLSchema-versioning" vc:minVersion="1.1">
    <xs:element name="root">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="Action">
                    <xs:simpleType>
                        <xs:restriction base="xs:string">
                            <xs:enumeration value="New"/>
                            <xs:enumeration value="Update"/>
                            <xs:enumeration value="Delete"/>
                        </xs:restriction>
                    </xs:simpleType>
                </xs:element>
                <xs:element name="UpdateReason"/>
            </xs:sequence>
            <xs:assert test="not(Action = 'Update') or normalize-space(UpdateReason)"/>
        </xs:complexType>
    </xs:element>
</xs:schema>

Open in new window

0
 

Author Closing Comment

by:GouthamAnand
ID: 40006767
Thanks a lot. I am not using XSD1.1
0
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 40006955
OK, that is a disappointment then
- you could consider embedding schematron assertions (most parsers allow that, put the schematron assertions in their own namespace in the annotation)
- you could consider schematron validation after schema validation (that is for instance how Python supports that)
- or you could have a simple reporting XSLT to tell you wrong or right
0
 
LVL 60

Expert Comment

by:Geert Bormans
ID: 40103467
Hi,
How did that work for you?
Maybe you could reconsider using XSD1.1, most parsers did implement at least the assertion bit
0

Featured Post

Turn Insights Into Action

You’ve already invested in ITSM tools, chat applications, automation utilities, and more. Fortify these solutions with intelligent communications so you can drive business processes forward.

With xMatters, you'll never miss a beat.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Many times as a report developer I've been asked to display normalized data such as three rows with values Jack, Joe, and Bob as a single comma-separated string such as 'Jack, Joe, Bob', and vice versa.  Here's how to do it. 
Create a Windows 10 custom Image with custom task bar and custom start menu using XML for deployment.
NetCrunch network monitor is a highly extensive platform for network monitoring and alert generation. In this video you'll see a live demo of NetCrunch with most notable features explained in a walk-through manner. You'll also get to know the philos…
If you’ve ever visited a web page and noticed a cool font that you really liked the look of, but couldn’t figure out which font it was so that you could use it for your own work, then this video is for you! In this Micro Tutorial, you'll learn yo…

690 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question