computed age column

Posted on 2014-04-17
Last Modified: 2014-04-18
I want a computed age column based on DOB.  What the best way to do this?  Is there a built in age function?
Question by:HLRosenberger
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
LVL 33

Accepted Solution

Big Monty earned 250 total points
ID: 40007048
no, but you can do something like this:

DECLARE @dob  datetime
SET @dob='1992-01-09 00:00:00'

SELECT DATEDIFF(hour,@dob,GETDATE())/8766.0 AS AgeYearsDecimal
    ,CONVERT(int,ROUND(DATEDIFF(hour,@dob,GETDATE())/8766.0,0)) AS AgeYearsIntRound
    ,DATEDIFF(hour,@dob,GETDATE())/8766 AS AgeYearsIntTrunc

Open in new window

LVL 69

Assisted Solution

by:Scott Pletcher
Scott Pletcher earned 250 total points
ID: 40007135
>> What the best way to do this? <<

Here's my preferred method.

    DATEDIFF(YEAR, dob, GETDATE()) - CASE WHEN CONVERT(char(5), dob, 1) > CONVERT(char(5), GETDATE(), 1) THEN 1 ELSE 0 END as age

Leap year birthdays are the tricky part.  The code above treats Mar 1 as the birthday for someone born on Feb 29.  Code will need adjusted if you need to consider Feb 28 their birthday in non-leap years (believe it or not, some govts actually have laws on how this needs calculated, esp. for retirement, years-of-service, etc.).

>>  Is there a built-in age function? <<

Author Closing Comment

ID: 40009258
Online Training Solution

Drastically shorten your training time with WalkMe's advanced online training solution that Guides your trainees to action. Forget about retraining and skyrocket knowledge retention rates.

LVL 69

Expert Comment

by:Scott Pletcher
ID: 40009345
Interesting choice.  Exactly one year (or nn years) after my birthday, shouldn't I be one year (or nn years) old?!

DECLARE @dob  datetime

SELECT @dob AS date_of_birth, GETDATE() AS todays_date,
    DATEDIFF(hour,@dob,GETDATE())/8766 AS AgeYearsIntTrunc


SELECT @dob AS date_of_birth, GETDATE() AS todays_date,
    DATEDIFF(hour,@dob,GETDATE())/8766 AS AgeYearsIntTrunc

Author Comment

ID: 40009435

I do not follow.  I'm working with both solutions trying to get he correct age.
LVL 69

Expert Comment

by:Scott Pletcher
ID: 40009584
OK, good luck.  I can't imagine that an hours-based method could ever be fully accurate.

Featured Post

Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Why is this different from all of the other step by step guides?  Because I make a living as a DBA and not as a writer and I lived through this experience. Defining the name: When I talk to people they say different names on this subject stuff l…
This article shows gives you an overview on SQL Server 2016 row level security. You will also get to know the usages of row-level-security and how it works
Familiarize people with the process of utilizing SQL Server functions from within Microsoft Access. Microsoft Access is a very powerful client/server development tool. One of the SQL Server objects that you can interact with from within Microsoft Ac…
Using examples as well as descriptions, and references to Books Online, show the documentation available for date manipulation functions and by using a select few of these functions, show how date based data can be manipulated with these functions.

627 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question