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How to split words into | (pipe sign)

Posted on 2014-04-25
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Last Modified: 2014-04-25
Hi there

Hope all is ok.

I have this code:

    function fun_get() {
        var ele = jQuery('input[name=CheckboxStatus]:checked').map(function () {
            return this.value;
        }).get().join()
      
        return ele;
    }

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and I have a checkbox when I select for example the checkbox "blue" and running the function above I get:

blue

HOWEVER, if I check 2 or more checkboxes I get

blue,red,green

can someone please help me with the JS code, What I want is if I select 1 option it should be for example (as seen below):

blue

If I select more then 1 it should be

blue|red|green

as you can see it places a pipe sign IF there are more then 1 selected, also as you can see there is NOT a pipe sign at the end of the string.

hope someone can come back to me.

thanks
0
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Question by:mousemat24
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8 Comments
 
LVL 22

Expert Comment

by:plusone3055
ID: 40022677
a
0
 

Author Comment

by:mousemat24
ID: 40022683
it is part of jquery
0
 

Author Comment

by:mousemat24
ID: 40022688
or I can use this, but it still creates the same problem

    function getCheckBoxValues(checkboxName) {
        var checkboxVals = [];
        $('input:checkbox[name=CheckboxStatus]:checked').each(function (index) {
            checkboxVals.push($(this).val());            
        })          
    }

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LVL 22

Accepted Solution

by:
plusone3055 earned 2000 total points
ID: 40022692
the separation is happening inside the JQuery script with the Comma

not with in the code you provided.

search through the jQuery script (particulalrly the join function)  and find the Comma separator and change the  "," to a "|" and you'll be good to go  :)
0
 

Author Comment

by:mousemat24
ID: 40022697
problem is I cant really do that, because some other part of the site uses that
0
 
LVL 22

Expert Comment

by:plusone3055
ID: 40022703
never fear
duplicate the join function in the Jquery and call it Join2 and use the join2 function where you need it.
0
 

Author Closing Comment

by:mousemat24
ID: 40022704
you are correct, all I had to do was


join("|")
0
 

Author Comment

by:mousemat24
ID: 40022705
thanks for the tip
0

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