Solved

SQL Server scalar function

Posted on 2014-04-28
4
460 Views
Last Modified: 2014-04-29
Hi,

I want a scalar function in SQL Server that checks if ID exists in the table, if it does then find if userid for that ID exists. If both are true then return 1 else return 0.

Here's my code:
CREATE FUNCTION dbo.ufnCheckIDAndUSERID(@ID varchar)
RETURNS bit
AS
BEGIN
--first check if the ID is there in SQL table:
IF ((SELECT count(ID) from [mydb].[dbo].[t] where ID = @ID) = 1)
AND
((SELECT count(UserID) from [mydb].[dbo].[t] where ID = @ID)=1)
RETURN 1
ELSE
RETURN 0
END;

Open in new window


I m getting
Msg 156, Level 15, State 1, Procedure ufnCheckDistrictAndntid, Line 7
Incorrect syntax near the keyword 'IF'.

I m a newbie using SQL function. ANy clue to resolve it? Thanks.
0
Comment
Question by:dearnemo
  • 2
4 Comments
 
LVL 21

Accepted Solution

by:
Dale Burrell earned 500 total points
ID: 40028595
You can only have one return statement in a function and it must be last.

create function dbo.ufnCheckIDAndUSERID
(
  @Id varchar(38)
)
returns bit
as
begin
  declare @Result bit

  --first check if the ID is there in SQL table:
  if ((select count(ID) from mydb.dbo.t where ID = @Id) = 1) AND ((select count(UserID) from mydb.dbo.t where ID = @Id) = 1) set @Result = 1

  return @Result
end

Open in new window

0
 

Author Closing Comment

by:dearnemo
ID: 40028603
Ty very much for your prompt response. :)
0
 
LVL 21

Expert Comment

by:Dale Burrell
ID: 40028608
No worries, actually just realised if you use my code you need to add a line after declare...

set @Result = 0
0
 
LVL 48

Expert Comment

by:PortletPaul
ID: 40029109
Is the field [t].[ID] bigint or varchar?

if it is a big integer then your parameter should be bigint

why scan the table twice?

    CREATE TABLE T
    	([ID] int, [UserID] varchar(5))
    ;
    	
    INSERT INTO T
    	([ID], [UserID])
    VALUES
    	(101, 'Fred'),
    	(102, 'Wilma')
    ;

**Query 1**:

    declare @Id varchar(38)
    
    set @Id = '101'
    
    
    SELECT count(ID) from [dbo].[t] where ID = @ID 
    union all
    SELECT count(UserID) from [dbo].[t] where ID = @ID 
    
    

**[Results][2]**:
    
    | COLUMN_0 |
    |----------|
    |        1 |
    |        1 |


**Query 2**:

    declare @Id varchar(38)
    
    set @Id = '101'
    
    SELECT
           count(id) + count(UserID)
    from [dbo].[t]
    where id = @id
    

**[Results][3]**:
    
    | COLUMN_0 |
    |----------|
    |        2 |



  [1]: http://sqlfiddle.com/#!3/05979/13

Open in new window

0

Featured Post

Microsoft Certification Exam 74-409

Veeam® is happy to provide the Microsoft community with a study guide prepared by MVP and MCT, Orin Thomas. This guide will take you through each of the exam objectives, helping you to prepare for and pass the examination.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction SQL Server Integration Services can read XML files, that’s known by every BI developer.  (If you didn’t, don’t worry, I’m aiming this article at newcomers as well.) But how far can you go?  When does the XML Source component become …
Ever needed a SQL 2008 Database replicated/mirrored/log shipped on another server but you can't take the downtime inflicted by initial snapshot or disconnect while T-logs are restored or mirror applied? You can use SQL Server Initialize from Backup…
Familiarize people with the process of utilizing SQL Server functions from within Microsoft Access. Microsoft Access is a very powerful client/server development tool. One of the SQL Server objects that you can interact with from within Microsoft Ac…
Using examples as well as descriptions, and references to Books Online, show the documentation available for datatypes, explain the available data types and show how data can be passed into and out of variables.

911 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

15 Experts available now in Live!

Get 1:1 Help Now