problem with a instr function on microsoft access 2013 vba

hi

i have a code like this
    
Set TDS = db.TableDefs
On Error GoTo Err_Proc
'Loop through the tables collection
    For Each td In TDS
        If td.Connect = ";DATABASE=" & OldPathName Then
            msgbox "find Table"
        end if

Open in new window

this code is working just fine, but when  i tried a similar code that contain a instr function i get an error 13-type mismatch

this the not working code
 If td.Connect = InStr(1, td.Connect, """ & OldPathName & """) <> 0 Then

Open in new window


how can i fix this code to be able to use instr
thanks
bill201Asked:
Who is Participating?
 
NorieConnect With a Mentor VBA ExpertCommented:
InStr returns a number so you can't compare it to a string, which is what I assume td.Connect returns.

To check if OldPathName is in td.Connect check if InStr returns a  value more than 0.
If InStr(td.Connect,  OldPathName) <> 0 Then 

Open in new window

0
 
ukerandiCommented:
Try to use  Cint( instr
0
 
bill201Author Commented:
ukerandi Thank you too, but it did not solve the problem, But thanks to the desire
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.