asked on # How to add variable string in unix

I have string A which has value dynamical comming form database.

I want to add that string + 1 and get the output.

For example:

A=05

I want add this variable +1.

B=$A+1

and desired outpu should be 05+1= 06.

Output should be 06.

Note I am using ksh script.

Can you please reply as soon as possible.

Thanks,

Sailaja.

I want to add that string + 1 and get the output.

For example:

A=05

I want add this variable +1.

B=$A+1

and desired outpu should be 05+1= 06.

Output should be 06.

Note I am using ksh script.

Can you please reply as soon as possible.

Thanks,

Sailaja.

Unix OS

I beleve dc operator can be used.

I am geting the result as 6 I want the result as 06 how we get that.

BD0_MON=05

val=`expr $BD0_MON + 1`

6

desired output 06

BD0_MON=05

val=`expr $BD0_MON + 1`

6

desired output 06

B=$(echo $A | awk '{printf "%02d", $1+1}')

Or like this:

B=$(awk -v A="$A" 'BEGIN {printf "%02d", A+1}')

Under bash this works as well:

B=$(awk '{printf "%02d", $1+1}' <<<$A)

Or like this:

B=$(awk -v A="$A" 'BEGIN {printf "%02d", A+1}')

Under bash this works as well:

B=$(awk '{printf "%02d", $1+1}' <<<$A)

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If it's for calculating months so that you want 12 + 1 to become 01 try this:

B=$(echo $A | awk '{printf "%02d", ($1+1)%12}')

B=$(awk '{printf "%02d", ($1+1)%12}' <<<$A) # BASH

B=$(awk -v A="$A" 'BEGIN {printf "%02d", (A+1)%12}')

B=$(echo $A | awk '{printf "%02d", ($1+1)%12}')

B=$(awk '{printf "%02d", ($1+1)%12}' <<<$A) # BASH

B=$(awk -v A="$A" 'BEGIN {printf "%02d", (A+1)%12}')

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Sorry, *ozo*, my arithmetic skills are indeed quite rusty, but I can't see the difference.

Example "7":

My version: 7 + 1 gives 8. Dividing 8 by 12 gives remainder 8.

Your version: Dividing 7 by 12 gives remainder 7. 7 + 1 gives 8.

Example "12":

My version: 12 + 1 gives 13. Dividing 13 by 12 gives remainder 1.

Your version: Dividing 12 by 12 gives remainder 0. 0 + 1 gives 1.

(m+1)%n = m%n+1

OK, your version saves a pair of parentheses.

Confused:

wmp

Example "7":

My version: 7 + 1 gives 8. Dividing 8 by 12 gives remainder 8.

Your version: Dividing 7 by 12 gives remainder 7. 7 + 1 gives 8.

Example "12":

My version: 12 + 1 gives 13. Dividing 13 by 12 gives remainder 1.

Your version: Dividing 12 by 12 gives remainder 0. 0 + 1 gives 1.

(m+1)%n = m%n+1

OK, your version saves a pair of parentheses.

Confused:

wmp

Example, "11"

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I saw that coming ...

Thanks for the lesson!

wmp

Thanks for the lesson!

wmp

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