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PHP Multidimensional array show only one value

acbv
acbv asked
on
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Last Modified: 2014-05-09
Hello I have this array:
 [41] => Array
        (
            [type] => locations
            [name] => LOCATION
            [keyword] => Array
                (
                    [5] => City
                    [4] => Region
                    [3] => Regional District
                    [2] => Province
                    [1] => LOCATION1
                )

            [value] => Array
                (
                    [5] => Grande Prairie
                    [4] => Grande Prairie
                    [3] => Grande Prairie
                    [2] => Alberta
                    [1] => Canada
                )
How can I modify this code in order to show only the city?:

foreach ($property[41]['value'] as $ind=>$lval)
            {
                  $location_string .= $lval .', ';
            }
Thanks!!!
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Top Expert 2015

Commented:
How about this?:
foreach ($property[41] as $ind=>$lval)
            {
		if ($ind === "keyword" && is_array($lval)) {
			$location_string .= $property[41]['value'][array_search("City", array_keys($lval))] . ', ';
		}
            }

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Author

Commented:
Is not working
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Top Expert 2015

Commented:
Sorry to hear that.

Based on what you have posted as the contents of index 41, the code I provided should loop through the contents, look for "keyword" in the $ind variable key then check to see that its value is an array. When the conditions are met, it pulls the value positioned at the same index as "City" from the "keyword" sub array from the "value" sub array. Simple logic, I don't see anything wrong with my code so I cannot explain why it's not working for you.

Perhaps you can provide more information or maybe a PHP expert will assist further.

Author

Commented:
I found it:
if (isset( $property[41]))
                  $location_string .= $property[41]['value'][5];

Thanks anyway for your help, very much appreciated!
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Top Expert 2015
Commented:
This one is on us!
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