JSONArray and mysqlli

//old mysql conn
$json_arr = array("r1" => $row["r1"],"r2" => $row["r2"] );
  echo json_encode( $json_arr );

return :
{"r1":"3610","r2":"0.0000" }

and this is ok.

//new mysql conn
when i use mysqlli
  $row = $rs->fetch_all(MYSQLI_ASSOC);
 echo json_encode( $row );

[{"r1":"3610","r2":"0.0000" }]

and this is not work.

What the problem?

Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

I don't see any problem
what about :
$row = $rs->fetch_all(MYSQLI_ASSOC);
 echo json_encode( $row[0] );

Open in new window


Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
imediagroupAuthor Commented:
i need like this     {"r1":"3610","r2":"0.0000" }

but return     [{"r1":"3610","r2":"0.0000" }]

problem []
imediagroupAuthor Commented:
oh thanks..

problem is   echo json_encode( $row[0] );  and i use  echo json_encode( $row);
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.