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That's excellent.<br />
Many thanks<br />
Toco
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I should have asked, what does the 10^10 do ?
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I should have asked, what does the 10^10 do ?

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It's 10 to the power of 10 (i.e. a very large number).<br />
<br />
Lookup() looks for that number in the range Manchester_RNL_Budget[@[Ja<wbr />nuary]:[De<wbr />cember]]. &nbsp;If it doesn't find it (which it won't), then the function is designed to return the last value that is less than or equal to the lookup value. &nbsp;This will be your single value in each row.
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It's 10 to the power of 10 (i.e. a very large number).

Lookup() looks for that number in the range Manchester_RNL_Budget[@[January]:[December]].  If it doesn't find it (which it won't), then the function is designed to return the last value that is less than or equal to the lookup value.  This will be your single value in each row.

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<div class="content wysiwyg-content">
Hi All,<br />
<br />
I have an Excel 2010 table which consists of some Client details and the 12 months of the year as column headings. For each Client row there is a sales amount in ONE of the January to December columns.<br />
<br />
I want to populate a new column (called Month) depending on which Jan to Dec column has the sales amount. So, if a sales figure of £5,600 is in the column headed 'April', then I want the Month column to be populated with the text item &quot;April&quot;.<br />
<br />
Is there a more efficient way of calculating this than using a large nested IF formula testing each cell in the Jan to Dec columns ?<br />
<br />
I've attached a cut-down version of the sheet for clarity.<br />
<br />
Thanks in anticipation<br />
Toco<br />
<a href="https://filedb.experts-exchange.com/incoming/2014/07_w29/861022/ExampleClientSheet.xlsx" target="_blank" class="file-inline" title="Client amounts in a single month (364 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>ExampleClientSheet.xlsx</a>
</div>
</div>


ExampleClientSheet.xlsx

Hi All,

I have an Excel 2010 table which consists of some Client details and the 12 months of the year as column headings. For each Client row there is a sales amount in ONE of the January to December columns.

I want to populate a new column (called Month) depending on which Jan to Dec column has the sales amount. So, if a sales figure of £5,600 is in the column headed 'April', then I want the Month column to be populated with the text item "April".

Is there a more efficient way of calculating this than using a large nested IF formula testing each cell in the Jan to Dec columns ?

I've attached a cut-down version of the sheet for clarity.

Thanks in anticipation
Toco

How do I return an Excel table column heading based on a table value ?

Microsoft Excel topics include formulas, formatting, VBA macros and user-defined functions, and everything else related to the spreadsheet user interface, including error messages.