how to split the string

Hi i have ah string like this

String s = add(add(12,5),5)
I want to split this first i want to do inside add then come to out side
LVL 20
Sathish David  Kumar NArchitectAsked:
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Sathish David Kumar NArchitectAuthor Commented:
I want yo change that into
No((no(12)+no(5))+no(5)) how do this
0
duncanb7Commented:
Why you mention split string ? If using split() to split string with delimiter
of "-",for example, the code will be this

String string = "004-034556";
String[] parts = string.split("-");
String part1 = parts[0]; // 004
String part2 = parts[1]; // 0

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Could you write it more and in detail

Duncan
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CEHJCommented:
You can't really handle nesting well with regular expressions. What you're doing is dealing with a mini-language so you need to create a parser for it
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Sathish David Kumar NArchitectAuthor Commented:
Praser?? Can you give some example?
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Sathish David Kumar NArchitectAuthor Commented:
Chj can you tell how implement in my example string
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CEHJCommented:
Sorry - no. I have no experience with it personally
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rrzCommented:
If you want
add(add(12,5),5)  to change to  No((no(12)+no(5))+no(5))      
import java.util.regex.*;
public class Test {
   public static void main(String args[]){
    String s = "add(add(12,5),5)";
	Pattern p = Pattern.compile("-?\\d+");
        Matcher m = p.matcher(s);
	StringBuilder sb = new StringBuilder("No((");
	while (m.find()) {
		sb.append("no(" + m.group() + ")+");
	}
	sb.deleteCharAt(sb.length() - 1);
	sb.append(")");
    System.out.print(sb.toString());
   }
}

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awking00Commented:
I suspect your example is a sample representation of some real data that probably has more than one variation. Perhaps you can provide some different samples and, most importantly, an explicit explanation of the criteria to employ to produce your desired results.
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