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Increase Numbers containing letters.

I have a registration routine
the credit card company that processes purchases needs a list of valid unlocking numbers.
each time a purchase is made the user is given the next unlocking number
I want to give them a list of 100 valid numbers are between 5000 and 9900
a valid entry could be yjk50kg00dky
with the number subtracted from the string it would be 5000
The next valid number would be yjk50kg01dky the nummbers in the string = 5001
the next 5002
the next 5003
all the way to a hundred.
the string would stay the same "yjkkgdky"

every number would be incremeted by 1
How to write this ?
0
isnoend2001
Asked:
isnoend2001
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1 Solution
 
Martin LissRetired ProgrammerCommented:
    Dim str1 As String
    Dim str2 As String
    Dim str3 As String
    Dim str4 As String
    Dim str5 As String
    Dim intNum As Integer
    Dim strNewUnlock As String
    
    
    str1 = Left$(LastUnlockNumber, 2)
    str2 = Mid$(LastUnlockNumber, 4, 2)
    str3 = Mid$(LastUnlockNumber, 6, 2)
    str4 = Mid$(LastUnlockNumber, 8, 2)
    str5 = Right$(LastUnlockNumber, 2)
    
    intNum = str2 & str4
    intNum = intNum + 1
    
    strNewUnlock = str1 & Left$(CStr(intNum), 2) & str3 & Right$(CStr(intNum), 2) & str5

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Martin LissRetired ProgrammerCommented:
If the letters are always the same you could just do

    Dim str1 As String
    Dim str2 As String
    Dim strNewUnlock As String
    
    
    str1 = Mid$(LastUnlockNumber, 4, 2)
    str2 = Mid$(LastUnlockNumber, 8, 2)
    
    intNum = str1 & str2
    intNum = intNum + 1
    
    strNewUnlock = "yjk" & Left$(CStr(intNum), 2) & "kg" & Right$(CStr(intNum), 2) & "dky"

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Martin LissRetired ProgrammerCommented:
And I guess that it's unlikely to happen but maybe you should add lines 11 to 14.

 Dim str1 As String
    Dim str2 As String
    Dim strNewUnlock As String
    
    
    str1 = Mid$(LastUnlockNumber, 4, 2)
    str2 = Mid$(LastUnlockNumber, 8, 2)
    
    intNum = str1 & str2
    intNum = intNum + 1
    If intNum > 9900 Then
        MsgBox "Too Large"
        Exit Sub
    End If
    
    strNewUnlock = "yjk" & Left$(CStr(intNum), 2) & "kg" & Right$(CStr(intNum), 2) & "dky"

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isnoend2001Author Commented:
Thanks martinliss.
this is unneeded
If intNum > 9900 Then
        MsgBox "Too Large"
        Exit Sub
    End If
This is just a list of valid numbers to give the credit card company
I plan on just outputing the list to the debug window and pasting the numbers into their online screen.
in looking at your code should it be put into a loop 1-100 ?
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isnoend2001Author Commented:
what is this variable LastUnlockNumber ?
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isnoend2001Author Commented:
Martin I used your code to write this sub:

Sub OutPutRegistractionNumbers() 'temp to output for online code disburstment
Dim i As Integer
Dim LastUnlockNumber As String
 Dim str1 As String
 Dim intNum As Long
    Dim str2 As String
    Dim strNewUnlock As String
     LastUnlockNumber = "yjk50kg01dky"
    
   For i = 1 To 100
    str1 = Mid$(LastUnlockNumber, 4, 2)
    str2 = Mid$(LastUnlockNumber, 8, 2)
    
    intNum = str1 & str2
    intNum = intNum + 1
    
    strNewUnlock = "yjk" & Left$(CStr(intNum), 2) & "kg" & Right$(CStr(intNum), 2) & "dky"
    Debug.Print strNewUnlock
    Next
    
End Sub

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but the debug showed :
yjk50kg02dky
yjk50kg02dky sb yjk50kg03dky
yjk50kg02dky sb yjk50kg04dky

increase to 100
last number(100) sb yjk51kg00dk
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Martin LissRetired ProgrammerCommented:
You can use it as a function. If you run the "test" sub you will get:

Input: yjk50kg01dky output: yjk50kg02dky
Input: yjk50kg55dky output: yjk50kg56dky
Input: yjk50kg99dky output: yjk51kg00dky

Sub test()
OutPutRegistractionNumbers "yjk50kg01dky"
OutPutRegistractionNumbers "yjk50kg55dky"
OutPutRegistractionNumbers "yjk50kg99dky"
End Sub

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Public Function OutPutRegistractionNumbers(LastUnlockNumber) As String 'temp to output for online code disburstment

 Dim str1 As String
 Dim intNum As Long
    Dim str2 As String
    Dim strNewUnlock As String
    
    str1 = Mid$(LastUnlockNumber, 4, 2)
    str2 = Mid$(LastUnlockNumber, 8, 2)
    
    intNum = str1 & str2
    intNum = intNum + 1
    
    strNewUnlock = "yjk" & Left$(CStr(intNum), 2) & "kg" & Right$(CStr(intNum), 2) & "dky"
    Debug.Print "Input: " & LastUnlockNumber & " output: " & strNewUnlock
    
End Function

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isnoend2001Author Commented:
I did this
OutPutRegistractionNumbers ("yjk500kg10dky")
got a type mismatch on this line:
 intNum = str1 & str2
Am i doing something wrong?
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isnoend2001Author Commented:
I see i did this too high 500
valid numbers 5000 to 99100
sb yjk50kg001dky the number would be 5001
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Martin LissRetired ProgrammerCommented:
When you said "I want to give them a list of 100 valid numbers are between 5000 and 9900" was that correct or is it 5000 to 99100"?
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isnoend2001Author Commented:
5000 and 9900
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isnoend2001Author Commented:
sb
 low number yjk50kg01dky = 5001
to
high number yjk51kg00dky= 5100
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isnoend2001Author Commented:
I think i have to upload a hundred unlocking codes. When it gets less than 100 an someone makes a purchase I get a warning: "Low available licenses, please upload more
Each time a user buys the software they are given the first number on the list. I think the number is removed from the list so no 2 users get the same number
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Martin LissRetired ProgrammerCommented:
OK I'm confused but have I answered your original question? If not please tell me specifically what you need.
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isnoend2001Author Commented:
Thanks martinliss, but i do see how that code outputs 100 numbers. do i put it into a loop or ?
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Martin LissRetired ProgrammerCommented:
OK given a starting value, this will print out the next 100.

Sub test()
OutPutRegistractionNumbers "yjk50kg01dky"

End Sub

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Public Sub OutPutRegistractionNumbers(strStartingValue)
Dim i As Integer
 Dim str1 As String
 Dim intNum As Long
    Dim str2 As String
    Dim strNewUnlock As String
    Dim lngIndex As Long
    
    str1 = Mid$(strStartingValue, 4, 2)
    str2 = Mid$(strStartingValue, 8, 2)
    
    intNum = str1 & str2
    
    For lngIndex = 1 To 100
        intNum = intNum + 1
        Debug.Print "yjk" & Left$(CStr(intNum), 2) & "kg" & Right$(CStr(intNum), 2) & "dky"
    Next
    
End Sub

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isnoend2001Author Commented:
Perfect, Thank you
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Martin LissRetired ProgrammerCommented:
You're welcome.
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