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# Increase Numbers containing letters.

Posted on 2014-07-25
Medium Priority
136 Views
Last Modified: 2014-07-25
I have a registration routine
the credit card company that processes purchases needs a list of valid unlocking numbers.
each time a purchase is made the user is given the next unlocking number
I want to give them a list of 100 valid numbers are between 5000 and 9900
a valid entry could be yjk50kg00dky
with the number subtracted from the string it would be 5000
The next valid number would be yjk50kg01dky the nummbers in the string = 5001
the next 5002
the next 5003
all the way to a hundred.
the string would stay the same "yjkkgdky"

every number would be incremeted by 1
How to write this ?
0
Question by:isnoend2001
• 10
• 8
18 Comments

LVL 49

Expert Comment

ID: 40220580
``````    Dim str1 As String
Dim str2 As String
Dim str3 As String
Dim str4 As String
Dim str5 As String
Dim intNum As Integer
Dim strNewUnlock As String

str1 = Left\$(LastUnlockNumber, 2)
str2 = Mid\$(LastUnlockNumber, 4, 2)
str3 = Mid\$(LastUnlockNumber, 6, 2)
str4 = Mid\$(LastUnlockNumber, 8, 2)
str5 = Right\$(LastUnlockNumber, 2)

intNum = str2 & str4
intNum = intNum + 1

strNewUnlock = str1 & Left\$(CStr(intNum), 2) & str3 & Right\$(CStr(intNum), 2) & str5
``````
0

LVL 49

Expert Comment

ID: 40220584
If the letters are always the same you could just do

``````    Dim str1 As String
Dim str2 As String
Dim strNewUnlock As String

str1 = Mid\$(LastUnlockNumber, 4, 2)
str2 = Mid\$(LastUnlockNumber, 8, 2)

intNum = str1 & str2
intNum = intNum + 1

strNewUnlock = "yjk" & Left\$(CStr(intNum), 2) & "kg" & Right\$(CStr(intNum), 2) & "dky"
``````
0

LVL 49

Expert Comment

ID: 40220589
And I guess that it's unlikely to happen but maybe you should add lines 11 to 14.

`````` Dim str1 As String
Dim str2 As String
Dim strNewUnlock As String

str1 = Mid\$(LastUnlockNumber, 4, 2)
str2 = Mid\$(LastUnlockNumber, 8, 2)

intNum = str1 & str2
intNum = intNum + 1
If intNum > 9900 Then
MsgBox "Too Large"
Exit Sub
End If

strNewUnlock = "yjk" & Left\$(CStr(intNum), 2) & "kg" & Right\$(CStr(intNum), 2) & "dky"
``````
0

Author Comment

ID: 40220605
Thanks martinliss.
this is unneeded
If intNum > 9900 Then
MsgBox "Too Large"
Exit Sub
End If
This is just a list of valid numbers to give the credit card company
I plan on just outputing the list to the debug window and pasting the numbers into their online screen.
in looking at your code should it be put into a loop 1-100 ?
0

Author Comment

ID: 40220617
what is this variable LastUnlockNumber ?
0

Author Comment

ID: 40220649
Martin I used your code to write this sub:

``````Sub OutPutRegistractionNumbers() 'temp to output for online code disburstment
Dim i As Integer
Dim LastUnlockNumber As String
Dim str1 As String
Dim intNum As Long
Dim str2 As String
Dim strNewUnlock As String
LastUnlockNumber = "yjk50kg01dky"

For i = 1 To 100
str1 = Mid\$(LastUnlockNumber, 4, 2)
str2 = Mid\$(LastUnlockNumber, 8, 2)

intNum = str1 & str2
intNum = intNum + 1

strNewUnlock = "yjk" & Left\$(CStr(intNum), 2) & "kg" & Right\$(CStr(intNum), 2) & "dky"
Debug.Print strNewUnlock
Next

End Sub
``````
but the debug showed :
yjk50kg02dky
yjk50kg02dky sb yjk50kg03dky
yjk50kg02dky sb yjk50kg04dky

increase to 100
last number(100) sb yjk51kg00dk
0

LVL 49

Expert Comment

ID: 40220816
You can use it as a function. If you run the "test" sub you will get:

Input: yjk50kg01dky output: yjk50kg02dky
Input: yjk50kg55dky output: yjk50kg56dky
Input: yjk50kg99dky output: yjk51kg00dky

``````Sub test()
OutPutRegistractionNumbers "yjk50kg01dky"
OutPutRegistractionNumbers "yjk50kg55dky"
OutPutRegistractionNumbers "yjk50kg99dky"
End Sub
``````
``````Public Function OutPutRegistractionNumbers(LastUnlockNumber) As String 'temp to output for online code disburstment

Dim str1 As String
Dim intNum As Long
Dim str2 As String
Dim strNewUnlock As String

str1 = Mid\$(LastUnlockNumber, 4, 2)
str2 = Mid\$(LastUnlockNumber, 8, 2)

intNum = str1 & str2
intNum = intNum + 1

strNewUnlock = "yjk" & Left\$(CStr(intNum), 2) & "kg" & Right\$(CStr(intNum), 2) & "dky"
Debug.Print "Input: " & LastUnlockNumber & " output: " & strNewUnlock

End Function
``````
0

Author Comment

ID: 40220831
I did this
OutPutRegistractionNumbers ("yjk500kg10dky")
got a type mismatch on this line:
intNum = str1 & str2
Am i doing something wrong?
0

Author Comment

ID: 40220837
I see i did this too high 500
valid numbers 5000 to 99100
sb yjk50kg001dky the number would be 5001
0

LVL 49

Expert Comment

ID: 40220854
When you said "I want to give them a list of 100 valid numbers are between 5000 and 9900" was that correct or is it 5000 to 99100"?
0

Author Comment

ID: 40220861
5000 and 9900
0

Author Comment

ID: 40220869
sb
low number yjk50kg01dky = 5001
to
high number yjk51kg00dky= 5100
0

Author Comment

ID: 40220871
I think i have to upload a hundred unlocking codes. When it gets less than 100 an someone makes a purchase I get a warning: "Low available licenses, please upload more
Each time a user buys the software they are given the first number on the list. I think the number is removed from the list so no 2 users get the same number
0

LVL 49

Expert Comment

ID: 40220880
OK I'm confused but have I answered your original question? If not please tell me specifically what you need.
0

Author Comment

ID: 40220891
Thanks martinliss, but i do see how that code outputs 100 numbers. do i put it into a loop or ?
0

LVL 49

Accepted Solution

Martin Liss earned 2000 total points
ID: 40220943
OK given a starting value, this will print out the next 100.

``````Sub test()
OutPutRegistractionNumbers "yjk50kg01dky"

End Sub
``````
``````Public Sub OutPutRegistractionNumbers(strStartingValue)
Dim i As Integer
Dim str1 As String
Dim intNum As Long
Dim str2 As String
Dim strNewUnlock As String
Dim lngIndex As Long

str1 = Mid\$(strStartingValue, 4, 2)
str2 = Mid\$(strStartingValue, 8, 2)

intNum = str1 & str2

For lngIndex = 1 To 100
intNum = intNum + 1
Debug.Print "yjk" & Left\$(CStr(intNum), 2) & "kg" & Right\$(CStr(intNum), 2) & "dky"
Next

End Sub
``````
0

Author Closing Comment

ID: 40220951
Perfect, Thank you
0

LVL 49

Expert Comment

ID: 40220960
You're welcome.
0

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