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Excel help

Hi,

I need help to reformulate statement below...it is returning an error..


=IF(X56 = 0,"NO ALLOWANCE"),IF(X56>=W56,"GOOD","BAD")
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LubinofS
Asked:
LubinofS
4 Solutions
 
MontoyaProcess Improvement MgrCommented:
what is the error you are getting? What do you want to formula to do?
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LubinofSAuthor Commented:
I am getting "#VALUE!"


Everytime values in column X are higher or equal than column Y I want to qualify it as "GOOD" , if not would  be "BAD" , however there would be an excepction when column X equal ZERO ( "NO ALLOWANCE" )
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MontoyaProcess Improvement MgrCommented:
=IF(A2 = 0,"NO ALLOWANCE",IF(A2>A3,"GOOD","Bad"))
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CorinTackNetwork EngineerCommented:
=IF(X56 = 0,"NO ALLOWANCE",IF(X56>=W56,"GOOD","BAD"))

This will test cell X56. If it is zero (or blank) it will return NO ALLOWANCE. If it is not blank, but greater than (or equal to) W56, it will return GOOD, otherwise it will return BAD.

I presume this is what you were looking to accomplish.
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LubinofSAuthor Commented:
Sorry, see correction below...

Everytime values in column X are higher or equal than column W I want to qualify it as "GOOD" , if not would  be "BAD" , however there would be an excepction when column X equal ZERO ( "NO ALLOWANCE" )
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MontoyaProcess Improvement MgrCommented:
basically, you didnt next your parentheses properly
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Rey Obrero (Capricorn1)Commented:
try this

=IF(X56 = 0,"NO ALLOWANCE",IF(X56>=W56,"GOOD","BAD"))
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LubinofSAuthor Commented:
I got it, thanks to all...
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