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How can I insert multiple check box values into my database using php and mysql?

I’m creating a employee training tracker... something that allows me to assign training items and retraining frequency for each user loaded in the database.  For a given user (user_id), I would like to display a dynamic list of training items (current items loaded in the database).  Then, using checkboxes, select the training items relevant to that user. For now, I just hardcoded the user_id (will change that later.  The form is submitting but nothing is hitting the database. Here is my code so far:
<?php

require_once 'scripts/app_config.php';
require_once 'scripts/database_connection.php';

//check for which boxes are selected then update database 
if(isset($_POST['$checkbox'])) { 
foreach($_POST['checkbox'] as $i) { 

$sql1="INSERT INTO user_training_items (item_id, user_id)VALUES('{$_POST['item_id'][$i]}', '{$_POST['user_id'][$i]}')";
$result1=mysql_query($sql1);
} 
} 
?> 
<form method="post" action="checkbox_form.php"> 
<?php
$sql="SELECT * FROM training_items";
$result=mysql_query($sql);

// Count table rows 
$count=mysql_num_rows($result);

$i = 0; 
while($rows=mysql_fetch_array($result)){ 
?>

<tr>
<td align="center" bgcolor="#FFFFFF"><input name="checkbox" type="checkbox" id="checkbox" value="<?php echo $i++;?>" /></td>
<td align="center"><? echo $rows['item_title'];?></td>
<input type="hidden" name="item_id" id="item_id" value="<? echo $rows['item_id'];?>"/>
<input type="hidden" name="user_id" id="user_id" value="1"/>
</tr>

<?php
}
?>

<input type="submit" name="Submit" value="Submit">
</form>

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My tables are:

training_items
item_id
item_title


user_training_items
item_id
user_id
0
chaddcarr
Asked:
chaddcarr
  • 2
2 Solutions
 
Terry WoodsIT GuruCommented:
This bit doesn't make sense:
if(isset($_POST['$checkbox'])) { 
foreach($_POST['checkbox'] as $i) { 

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What is the field name? Is it '$checkbox' or 'checkbox'? Those are two different things.

Can you output the contents of $_POST by running:
print_r($_POST);

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and copy and paste the data for us to see?
0
 
Terry WoodsIT GuruCommented:
Also I should mention the input fields in your form (with type checkbox) should all have the same name that's an array, like 'mycheckbox[]' which should then be available to PHP in $_POST['mycheckbox'].
0
 
chaddcarrAuthor Commented:
Thanks Terry,  incorporating both your comments, I ended up with the following code which works great.  I also added an } else { statement to clean it up a bit.  Thanks again!

<?php

require_once 'scripts/app_config.php';
require_once 'scripts/database_connection.php';

//check for which boxes are selected then update database 
if(isset($_POST['checkbox'])) { 
foreach($_POST['checkbox'] as $i) { 

$sql1="INSERT INTO user_training_items (item_id, user_id)VALUES('{$_POST['item_id'][$i]}', '{$_POST['user_id'][$i]}')";
$result1=mysql_query($sql1);
} 
echo "The records have been added to the user profile";
} else {

?> 
<form method="post" action="checkbox_form.php"> 
<?php
$sql="SELECT * FROM training_items";
$result=mysql_query($sql);

// Count table rows 
$count=mysql_num_rows($result);

$i = 0; 
while($rows=mysql_fetch_array($result)){ 
?>

<tr>
<td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $i++;?>" /></td>
<td align="center"><? echo $rows['item_title'];?></td>
<input type="hidden" name="item_id[]" id="item_id" value="<? echo $rows['item_id'];?>"/><br />
<input type="hidden" name="user_id[]" id="user_id" value="1"/>
</td>
</tr>

<?php
}
?>

<p><input type="submit" name="Submit" value="Add"></p>
</form>
<?php
}
?>

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0

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