How to insert a thick line after integer row in Excel.

I have an excel document. I have a macro doing a ton of formatting. One of the formatting options organizes the data by names in Column A and then after each name change it adds three spaces.

I'm looking for an additional macro code to then go to columns k-y and for each new person, sum the columns. Each month the row totals will change.

Example Excel Attached. The rows in yellow are the rows i need to create via VBA script. Essentially some how get the script to read down the column selected (B) and when it sees a break in numbers, insert the formula. Then continue down. The number of rows will always be different although in this one its 2 then 1 then 3.
BrandonProject Manager, IT Systems and Software DesignAsked:
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Glenn RayExcel VBA DeveloperCommented:
Attachment? :-)
BrandonProject Manager, IT Systems and Software DesignAuthor Commented:
Glenn RayExcel VBA DeveloperCommented:
The formulas in J, K, L, & M need to remain as they are, just copied down so that they apply on the total row.  The rest should be SUM() formulas.

I assume you want a thick border above the total row, but no other formatting, correct?

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Glenn RayExcel VBA DeveloperCommented:
Attached is a macro-enabled workbook with the following code that will add subtotals after each set of names (Add_Totals):
Sub Add_Totals()
    Dim rng As Range
    Dim cl As Object
    Dim r, c, x As Integer
    Dim strName As String
    Set rng = Range("A1:A" & Cells.SpecialCells(xlLastCell).Row)
    For Each cl In rng
        If (cl.Value = "") And (strName <> "") Then 'add total
            For c = 1 To 8
                cl.Offset(0, c).FormulaR1C1 = "=SUM(R[-" & x & "]C:R[-1]C)"
            Next c
            For c = 13 To 15
                cl.Offset(0, c).FormulaR1C1 = "=SUM(R[-" & x & "]C:R[-1]C)"
            Next c
            r = cl.Row
            cl.Offset(0, 9).Formula = "=IFERROR(I" & r & "/B" & r & ","""")"
            cl.Offset(0, 10).Formula = "=IFERROR((C" & r & "-E" & r & ")/C" & r & ","""")"
            cl.Offset(0, 11).Formula = "=IFERROR((D" & r & "-G" & r & ")/D" & r & ","""")"
            cl.Offset(0, 12).Formula = "=IFERROR(MIN(0.25,(C" & r & "-E" & r & "-F" & r & ")/C" & r & "),0.25)"
            strName = cl.Value 'should be blank
            x = 0
            With Range(cl.Offset(0, 1), cl.Offset(0, 15)).Borders(xlEdgeTop)
                .LineStyle = xlContinuous
                .ColorIndex = xlAutomatic
                .TintAndShade = 0
                .Weight = xlMedium
            End With
            strName = cl.Value
            If strName <> "" Then x = x + 1
        End If
    Next cl
End Sub

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Note that I also changed the formulas in columns J through M to use the IFERROR function, which is significantly shorter:
J1: =IFERROR(I1/B1,"")
K1: =IFERROR((C1-E1)/C1,"")
L1: =IFERROR((D1-G1)/D1,"")
M1: =IFERROR(MIN(0.25,(C1-E1-F1)/C1),0.25)

You may want to change your existing macro that builds these formulas to use the IFERROR versions here.

BrandonProject Manager, IT Systems and Software DesignAuthor Commented:
Increased points since there will be at least one followup. Thanks for the changes, i'll implement.

This worked well with a couple of exceptions that are my fault.

the first three rows are header rows so this should start at A4. Actually it should start at G4 and provide the calculations for G-U and all the way down to the end.

Does this make sense?
Glenn RayExcel VBA DeveloperCommented:
Okay...code and example file adjusted for change in layout.  Let me know if you have any further questions or issues.


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BrandonProject Manager, IT Systems and Software DesignAuthor Commented:
Glenn RayExcel VBA DeveloperCommented:
I'm glad I could help.
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