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Chadd C

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How can I call a "user_id" of a newly created record and use it as a variable on a Subsequent form?

Upon adding a new employee record, the user is passed to a form where training records are assigned to the new employee. I cannot pass the user_id to the records form as that is auto-incremented when the employee record is created. So, I think it best to pass a unique variable (email) in the URL instead, then create a query to retrieve the user_id on the records page.  Both the user_id and item_id will be added to a linking table when the form is submitted.

Here is my script for the redirect from my create-user.php page.

// Redirect the user to the page that displays user information
$link = trim($_REQUEST['email2']);
header("Location: create_user_training.php?link=$link");
exit();

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Which is passing the variable fine:
http://mysite.com/create_user_training.php?link=myemail@somedomain.com

And here is my code for the create_user_training.php page:
<?php

require_once 'scripts/app_config.php';
require_once 'scripts/database_connection.php';

//check for which boxes are selected then update database 
if(isset($_POST['checkbox'])) { 
foreach($_POST['checkbox'] as $i) { 

$sql1="INSERT INTO user_training_items (item_id, user_id)VALUES('{$_POST['item_id'][$i]}', '{$_POST['user_id'][$i]}')";
$result1=mysql_query($sql1);
} 
echo "Thank you!  Both the user and thier training records have been entered.  Have a great day!";
} else {
?>
<p>Please select which training items the user must accomplish</p> 
<form method="post" action="create_user_training.php"> 
<?php

$linked = "SELECT user_id FROM users where email = {$_POST['link']}";
$result2=mysql_query($linked);

$sql="SELECT * FROM training_items";
$result=mysql_query($sql);

// Count table rows 
$count=mysql_num_rows($result);

$i = 0; 
while($rows=mysql_fetch_array($result)){ 
?>

<tr>
<td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $i++;?>" /></td>
<td align="center"><? echo $rows['item_title'];?></td>
<input type="hidden" name="item_id[]" id="item_id" value="<? echo $rows['item_id'];?>"/><br />
<input type="hidden" name="user_id[]" id="user_id" value="<? echo $result2;?>"/>
</td>
</tr>

<?php
}
?>

<p><input type="submit" name="Submit" value="Add"></p>
</form>
<?php
}
?>

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As you can see, first it sees if the form has been submitted to itself, and if so, adds the necessary form data. If not, it presents the form in which the user selects the training items.  The item_id's are making it into the database but not the associated user_id.  Those are zeroed out. My guess the error resides in my attempt to define the user_id.

Any suggestions?
Avatar of Ray Paseur
Ray Paseur
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This is not rocket science, but you need to get at least some foundation in PHP and MySQL to begin a task like this.  This article can help you get started.  If you do not have the time to spend a couple of months studying PHP and MySQL in structured lessons, you might want to hire someone to build this application.  The tradeoff is really simple: time vs money.  
https://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/A_11769-And-by-the-way-I-am-new-to-PHP.html
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Avatar of Justin Pilditch
Justin Pilditch
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Avatar of Chadd C
Chadd C

ASKER

Thanks Murfur!  Most helpful!