SQLP pivot columns into new row column from duplicate key

I have created a table which contains a rownumber, memberid and Datestart,, dateEnd.  The problem is that I can have duplicate memberid's.  I need to interogate the date ranges on all the duplicate rows to do GAP analysis on the date ranges .  I have been searching for a PIVOT example to pivit the date columns into one row.

See the attached file for the problem visual. where the row is greater than 1 I need to add the dates to  the first.
Capture2.PNG
rschmehlAsked:
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PortletPaulfreelancerCommented:
I have almost no idea what you are asking for. Sorry if that seems rude, I'm just being honest.

>>"The problem is that I can have duplicate memberid's. "
are you trying to solve this?

>>"I need to interrogate the date ranges ... to pivot the date columns into one row."
is this the request?    ( If so, what does this actually mean? please provide an example)

The graphic does not reveal your problem to me (i.e. it isn't self evident ,,, to me)
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The best, most effective, and fastest way to get your message across is through the following:

A: Some sample data (ideally this is a table definition and some inserts; or it might simply be a copy/paste of some data into a code block. But is not an image of data, it is actual reusable data we can get into a table)

B: an "expected result"
This might be a graphic but more likely it would be an area of an Excel sheet that displays the output you are looking for. This should be based on the sample data.

With these we have the tools to understand the problem and to test if we can solve the problem. And you don't have to use so many words to describe the problem either.

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please provide some sample data and an expected result.
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Irek PiwowarekCommented:
As I understand your issue, you want to extend dates from row 1 by dates from row 2. I see some solutions here;
1. Left join by memeberid, memeberCIM (left side row 1 and right side row 2) this way you will remove duplicates and can extend dates
2. Group by memeberid, memeberCIM and find min from startdate and max from enddate (removes duplicates and extends dates)

I hope this helps.
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rschmehlAuthor Commented:
Thank you.
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Microsoft SQL Server 2008

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