extract numbers from text string

I have a table of data and one of the column contains a string.  The first set of charachters are always a number.  The second set of charachters are always letters.   I am trying to extract the first set of numeric charachters.  Using a simple left() function does not work becasue sometimes the numbers are one digit an sometimes they are two.  For example, the string may look like the following:




In the example above, I need to extract the '11' and the '1' respectively.

Thanks for your assistance.
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Will this work for you ?
Sub test()

Dim str As String
str_in = "09s8asdf098sd0985"
str_out = ""
For i = 1 To Len(str_in)
    If IsNumeric(Mid(str_in, i, 1)) Then
        str_out = str_out + Mid(str_in, i, 1)
    End If
Next i
MsgBox str_out

End Sub

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There's also a formula instead:


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assuming the string is in A1, and you put this formula in B1 (and finish with CTRL+SHIFT+ENTER, and sometimes regional settings make your formula use ; instead of , so change that if you see an error)
One slight flaw though, this only detects one number sequence (in essence, returns 11 when cell A1 is 11AA, but returns N/A when cell A1 is 11AA11)
Glenn RayExcel VBA DeveloperCommented:
You can find out the leftmost numeric characters with an array function.  

If your first value is in cell A2, enter this array formula (using [Ctrl]+[Shift]+[Enter):

It will produce the left-most digits only but as text, in case there are leading zeroes.  See the attached example file.


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Rob HensonFinance AnalystCommented:
Are they always just one or two digits?

If so this will suffice:


Where string of characters is in G30.

Rob H
Glenn RayExcel VBA DeveloperCommented:
If indeed there are always one or two leading digits and you want the number value, Rob's solution is best.  It's simple and faster than the array function I provided.

If there could be more than two characters - or if you need leading zeroes - or if there are no numbers - the array function will work.

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