UNIX shell script question

I am writing the following command in the shell script:
#!/bin/bash
var1=`/home/user1/Python/bin/bq --format prettyjson show mytab1 | grep "lastModifiedTime"`

The above returns:
  "lastModifiedTime": "1407393977076",

If I write:
var1=`/home/user1/Python/bin/bq --format prettyjson show mytab1 | grep "lastModifiedTime" | awk -F"\"" '{print $4}'`
The above returns 1407393977076

I only need the first 10 digits of the above number which is 1407393977
Could you please help me update the above command so that the above returns 1407393977 (not 1407393977076) ?
I need to preferably use a single command.
Thank you.
toookiAsked:
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serialbandCommented:
try this

var1=`/home/user1/Python/bin/bq --format prettyjson show mytab1 | grep "lastModifiedTime" | awk -F"\"" '{print $4}'`|cut -c 1-10

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nemws1Database AdministratorCommented:
Since you're going to have pretty static output, you can skip the awk and go right to the cut:
var1=`/home/user1/Python/bin/bq --format prettyjson show mytab1 | grep "lastModifiedTime" | cut -c 22-32`

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tel2Commented:
Well said, nemws1, except 22-32 is 11 chars, and we want 10.

Should be this:
    var1=`/home/user1/Python/bin/bq --format prettyjson show mytab1 | grep "lastModifiedTime" | cut -c22-31`
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nemws1Database AdministratorCommented:
Yup, off by one error on my part.
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toookiAuthor Commented:
Worked perfectly.
Thanks a lot.
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simon3270Commented:
grep then cut?  How about:

    var1=`/home/user1/Python/bin/bq --format prettyjson show mytab1 | awk '/lastModifiedTime/{print substr($0,21,10)}'
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