Is there a way to sort a query on odd/even numbers

I have a database of buildings.  I would like to sort it by odd/even address number.  Give me all the odds first followed by the evens.
breeze351Asked:
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Kyle AbrahamsSenior .Net DeveloperCommented:
yes:

order by
case when cast (address_number as int) % 2 = 1 then SELECT 0; 
else 
SELECT 1 ;
end case

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More on the case statement here:
http://dev.mysql.com/doc/refman/5.0/en/case.html

If you don't have address_number as its only field you can do a substring on the address column and use a char index to find the space between the number and the Street name.
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quizwedgeCommented:
Not sure, but this might be faster than a case statement. It's cleaner, at least.

select * 
from buildings 
order by address_number %2 = 0

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If you want the addresses in numerical order,

select * 
from buildings 
order by address_number %2 = 0, address_number

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breeze351Author Commented:
Thanks that works
0
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