NevSoFly
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dividing polynomials that don't divide evenly.
Using the long division method how would you solve(x^2-9-x)/(x+1) ? For example:
Unlike the above example x+1 won’t divide evenly into x^2-9-x, so what would be the result? Am I stuck with a remainder value or is there some kind of decimal point system?
Could someone please provide me with an example of how this would work (please include all steps).
thx
Unlike the above example x+1 won’t divide evenly into x^2-9-x, so what would be the result? Am I stuck with a remainder value or is there some kind of decimal point system? Could someone please provide me with an example of how this would work (please include all steps).
thx
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Correction: x-2 r -7
ASKER
So in that case there is no way to divide x^2-9-x by let's say a-b. Is this correct?
It seems confusing to me because I know that x^2/a can be written as x^2a^-1. I tried to do a similar problem like this but it would go on for eternity.
It seems confusing to me because I know that x^2/a can be written as x^2a^-1. I tried to do a similar problem like this but it would go on for eternity.
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ASKER
thanks, I got my answer and a bit of explanation.
>> x+1 won’t divide evenly into x^2-9-x
You have to keep your terms in order: x+1 won’t divide evenly into x² - x - 9
The final answer will be of the form: x - 2 + ( ????)/(x+1)
The ???? is the remainder