No, that is the answer. You will have a remainder of 7 as there is no value to evenly divide those polynomials.

x^2-9-x/x+1= x+2 r7

x^2-9-x/x+1= x+2 r7

Solved

Posted on 2014-08-19

Using the long division method how would you solve(x^2-9-x)/(x+1) ? For example:

Unlike the above example x+1 won’t divide evenly into x^2-9-x, so what would be the result? Am I stuck with a remainder value or is there some kind of decimal point system?

Could someone please provide me with an example of how this would work (please include all steps).

thx

Unlike the above example x+1 won’t divide evenly into x^2-9-x, so what would be the result? Am I stuck with a remainder value or is there some kind of decimal point system?

Could someone please provide me with an example of how this would work (please include all steps).

thx

6 Comments

x^2-9-x/x+1= x+2 r7

>> x+1 won’t divide evenly into x^2-9-x

You have to keep your terms in order: x+1 won’t divide evenly into

The final answer will be of the form: x - 2 + ( ????)/(x+1)

The ???? is the remainder

It seems confusing to me because I know that x^2/a can be written as x^2a^-1. I tried to do a similar problem like this but it would go on for eternity.

Title | # Comments | Views | Activity |
---|---|---|---|

springs | 9 | 217 | |

Representing TIME in Excel | 8 | 41 | |

What is the best statistical software to use for Excel 2007 for finding statistical patterns for probability factors? | 2 | 56 | |

Sample Space | 12 | 35 |

Join the community of 500,000 technology professionals and ask your questions.

Connect with top rated Experts

**16** Experts available now in Live!