Why is this PHP script throwing errors?

Why it this PHP script throwing errors?

<select name="q2" id="q2" required>
<option value="">---- Select One ----</option>
	$start_year = date('Y')-100;
	$end_year   = $start_year+100;						
	for($i=$start_year; $i<=$end_year; $i++) {				
		if ($_SESSION['q2'] == $i.date()) {					
			echo '<option value='.$i.date().' selected="selected">'.$i.date().'</option>';
		} else {				
			echo '<option value='.$i.date().'>'.$i.date().'</option>';				   

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When I view the underlying generated source code for this select dropdown,  I see the following error message for each iteration in the loop.  How can I modify my PHP script to eliminate it?

Warning:  date() expects at least 1 parameter, 0 given in /home/ideasdes/public_html/sts/index.html on line 1253

- Yvan
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Radek BaranowskiFull-stack Java DeveloperCommented:
This is not error, this is warning. Your program is probably working fine.
You can either specify date formattign string as described here: http://www.w3schools.com/php/func_date_date.asp

Or supress PHP warnings by using
at the beginning of your php script.

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I'm guessing, based on your code, where you have you date() you should be using
egoselfaxisAuthor Commented:
Right you are -- thank you very much!

- Yvan
Radek BaranowskiFull-stack Java DeveloperCommented:
nice one :) good luck.
Warnings are there for a reason, you don't just suppress them and pretend like they don't exists - the code is wrong and needs to be fixed
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