troubleshooting Question

2nd argument to copy algorithm in STL c++

Avatar of Pra Sys
Pra SysFlag for India asked on
C++Algorithms
11 Comments3 Solutions406 ViewsLast Modified:
I have this simple basic code which inserts array of strings in to vector of strings. This was written for purpose of test program.

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <iterator>

using namespace std;

int main()
{
    vector<string> strVec;

    string arr[4] = {"Foo","Bar","Baz","Bee"};
 
    copy(&arr[0], &arr[4], back_inserter(strVec));
    copy(strVec.begin(),strVec.end(),ostream_iterator<string>(cout, "\n"));
    return 0;
}

In the first use of "copy" above, why STL copy algorithm takes 2nd argument as an address of 5th element of array "arr" when it doesn't exists and how it actually treats it legally internally? Why such an "illegal" (it appears that way) arrangement is allowed?? Without that it copies one element less in to the vector. I could not find any explanation anywhere so would appreciate. Why cant it take address of last element i.e. &arr[3]??
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