Solved

Total Column to sum row

Posted on 2014-09-02
4
150 Views
Last Modified: 2014-09-02
I have a simple SQL Server cross tab select query. I'm trying to simply add a column at the far right named Total to add up the 7 column rows to the left but it keeps saying that its an invalid column name. I was trying to
Sum(A+B+C+D+E+F+G) AS Total

SELECT ProductsDetails.Gender, ProductsDetails.CorePN, ProductsDetails.productdescription, ProductsDetails.Color, ProductsDetails.Category, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 1 THEN Products.stockstatus ELSE 0 END) AS A, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 2 THEN Products.stockstatus ELSE 0 END) AS B, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 3 THEN Products.stockstatus ELSE 0 END) AS C, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 4 THEN Products.stockstatus ELSE 0 END) AS D, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 5 THEN Products.stockstatus ELSE 0 END) AS E, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 6 THEN Products.stockstatus ELSE 0 END) AS F, 
			SUM(CASE WHEN ProductsDetails.SizeNo = 7 THEN Products.stockstatus ELSE 0 END) AS G
FROM Products INNER JOIN ProductsDetails ON Products.productcode = ProductsDetails.productcode 
GROUP BY ProductsDetails.Site, ProductsDetails.Gender, ProductsDetails.CorePN, ProductsDetails.productdescription, ProductsDetails.Color, ProductsDetails.Category 
HAVING (ProductsDetails.Site LIKE N'Event Stock') 
ORDER BY ProductsDetails.Gender, ProductsDetails.CorePN, ProductsDetails.Category, ProductsDetails.Color

Open in new window

0
Comment
Question by:Southern_Gentleman
  • 3
4 Comments
 
LVL 75

Expert Comment

by:Anthony Perkins
Comment Utility
There are several ways of skinning this cat and it really depends on your version of SQL Server, if you are still using SQL Server 2000 you can do this:
SELECT  d.Gender,
	d.CorePN,
	d.productdescription,
	d.Color,
	d.Category,
	SUM(CASE WHEN d.SizeNo = 1 THEN p.stockstatus
		ELSE 0
	END) AS A,
	SUM(CASE WHEN d.SizeNo = 2 THEN p.stockstatus
		ELSE 0
	END) AS B,
	SUM(CASE WHEN d.SizeNo = 3 THEN p.stockstatus
		ELSE 0
	END) AS C,
	SUM(CASE WHEN d.SizeNo = 4 THEN p.stockstatus
		ELSE 0
	END) AS D,
	SUM(CASE WHEN d.SizeNo = 5 THEN p.stockstatus
		ELSE 0
	END) AS E,
	SUM(CASE WHEN d.SizeNo = 6 THEN p.stockstatus
		ELSE 0
	END) AS F,
	SUM(CASE WHEN d.SizeNo = 7 THEN p.stockstatus
		ELSE 0
	END) AS G,
	SUM(CASE WHEN d.SizeNo IN (1, 2, 3, 4, 5, 6, 7) THEN p.stockstatus
		ELSE 0
	END) AS Total
FROM    Products p
	INNER JOIN ProductsDetails d ON p.productcode = d.productcode
WHERE   d.[Site] LIKE N'Event Stock'
GROUP BY d.[Site],
	d.Gender,
	d.CorePN,
	d.productdescription,
	d.Color,
	d.Category
ORDER BY d.Gender,
	d.CorePN,
	d.Category,
	d.Color

Open in new window

Notice the way, that I am using aliases, this makes it easier to read.  Also, notice that I placed your condition in the WHERE clause instead of the HAVING.  Typically you use LIKE with wildcards so instead of say d.Site LIKE N'Event Stock', it could be d.Site LIKE N'Event Stock%'.  If you do want an exact match then I would write it as d.Site = N'Event Stock' and lose the d.Site in the GROUP BY clause
0
 
LVL 75

Accepted Solution

by:
Anthony Perkins earned 500 total points
Comment Utility
This can also be resolved with a derived table as follows:
SELECT Gender, CorePN, productdescription, Color, Category,
	A, B, C, D, E, F, G, A + B + C + D + E + F + G Total
FROM (SELECT	d.Gender,
		d.CorePN,
		d.productdescription,
		d.Color,
		d.Category,
		SUM(CASE WHEN d.SizeNo = 1 THEN p.stockstatus
			ELSE 0
		END) AS A,
		SUM(CASE WHEN d.SizeNo = 2 THEN p.stockstatus
			ELSE 0
		END) AS B,
		SUM(CASE WHEN d.SizeNo = 3 THEN p.stockstatus
			ELSE 0
		END) AS C,
		SUM(CASE WHEN d.SizeNo = 4 THEN p.stockstatus
			ELSE 0
		END) AS D,
		SUM(CASE WHEN d.SizeNo = 5 THEN p.stockstatus
			ELSE 0
		END) AS E,
		SUM(CASE WHEN d.SizeNo = 6 THEN p.stockstatus
			ELSE 0
		END) AS F,
		SUM(CASE WHEN d.SizeNo = 7 THEN p.stockstatus
			ELSE 0
		END) AS G,
		SUM(CASE WHEN d.SizeNo IN (1, 2, 3, 4, 5, 6, 7) THEN p.stockstatus
			ELSE 0
		END) AS Total
	FROM    Products p
		INNER JOIN ProductsDetails d ON p.productcode = d.productcode
	WHERE   d.[Site] LIKE N'Event Stock'
	GROUP BY d.[Site],
		d.Gender,
		d.CorePN,
		d.productdescription,
		d.Color,
		d.Category) a
ORDER BY
	Gender,
	CorePN,
	Category,
	Color

Open in new window

0
 
LVL 75

Expert Comment

by:Anthony Perkins
Comment Utility
If you are using SQL Server 2005 and up then you can resort to using a CTE or a PIVOT.
0
 

Author Closing Comment

by:Southern_Gentleman
Comment Utility
Thanks a bunch Anthony, I usually do alias for the tables but figure I give a little more description. Thanks again for the extra info and other ways to go about this.
0

Featured Post

How your wiki can always stay up-to-date

Quip doubles as a “living” wiki and a project management tool that evolves with your organization. As you finish projects in Quip, the work remains, easily accessible to all team members, new and old.
- Increase transparency
- Onboard new hires faster
- Access from mobile/offline

Join & Write a Comment

JSON is being used more and more, besides XML, and you surely wanted to parse the data out into SQL instead of doing it in some Javascript. The below function in SQL Server can do the job for you, returning a quick table with the parsed data.
The Delta outage: 650 cancelled flights, more than 1200 delayed flights, thousands of frustrated customers, tens of millions of dollars in damages – plus untold reputational damage to one of the world’s most trusted airlines. All due to a catastroph…
Via a live example, show how to backup a database, simulate a failure backup the tail of the database transaction log and perform the restore.
Viewers will learn how to use the INSERT statement to insert data into their tables. It will also introduce the NULL statement, to show them what happens when no value is giving for any given column.

728 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

11 Experts available now in Live!

Get 1:1 Help Now