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SQL query assistance requested

I have a table with the following fields:

ID (pk auto-generated)
PLACE_CODE
PLACE
TRAVELDATE
CITY
TRAVELTIME
QUALIFY

I am trying to create a query fo an MS Access DB that:
1) displays all fields,
2) only displays where CITY = 'Seattle'
3) sets TRAVELTIME = (TRAVELTIME/2) if QUALIFY = "YES"
4) GROUPS BY PLACECODE, PLACE, TRAVELDATE
5) only unique PLACECODE-PLACE-TRAVELDATE are displayed
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Cam Raben
Asked:
Cam Raben
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3 Solutions
 
Vitor MontalvãoMSSQL Senior EngineerCommented:
SELECT ID, PLACECODE, PLACE, TRAVELDATE, CITY,  iif(QUALIFY = "YES", (TRAVELTIME/2) , TRAVELTIME),  QUALIFY
FROM YourTableName
WHERE CITY = 'Seattle'
ORDER BY PLACECODE, PLACE, TRAVELDATE 

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Cam RabenAuthor Commented:
So how does this handle a TRAVELDATE with a time stamp on it?  For example, what if there were 2 TRAVELDATES = 01/22/2014, but with different time stamps?   I assume both would be displayed.  I really just want only one of those to appear, and it can be an average of the two.
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Vitor MontalvãoMSSQL Senior EngineerCommented:
Ok. But then ID shouldn't be returned.
I don't know if this going to work because I don't have Access here:
SELECT PLACECODE, PLACE, TRAVELDATE, CITY,  iif(QUALIFY = "YES", (TRAVELTIME/2) , TRAVELTIME),  QUALIFY
FROM YourTableName
WHERE CITY = 'Seattle'
GROUP BY PLACECODE, PLACE, TRAVELDATE 
ORDER BY PLACECODE, PLACE, TRAVELDATE 

Open in new window

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Cam RabenAuthor Commented:
It does not let me select all my fields, using the group by.  I was thinking here may be a special way to use the TRAVELDATE so that the timestamp is not in play.   ?
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Cam RabenAuthor Commented:
Any way to define TRAVELDATE as MM/DD/YYYY only, without the timestamp?
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Cam RabenAuthor Commented:
I keep working with this but it keeps giving me duplicate rows.  I need only unique PLACECODE-PLACE-TRAVELDATE to be displayed.   ?
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awking00Commented:
Can you post some sample data (just enough to demonstrate the issue) and what you expect as output?
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Cam RabenAuthor Commented:
The DB is way too large to send.  The issue is that the suggested code shown below does not return unique instances of [PLACECODE, PLACE, TRAVELDATE].  In other words, the query returns more than one row with [PLACECODE = 125, PLACE = "California", and TRAVELDATE = 01/22/2014], when it should return that combination only once.

SELECT ID, PLACECODE, PLACE, TRAVELDATE, CITY,  iif(QUALIFY = "YES", (TRAVELTIME/2) , TRAVELTIME),  QUALIFY
FROM YourTableName
WHERE CITY = 'Seattle'
ORDER BY PLACECODE, PLACE, TRAVELDATE
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awking00Commented:
No need to send entire DB. What are the results of the following query?
select top 25 id, placecode, place, traveldate, city, traveltime, qualify
from yourtable
where city = 'Seattle'
and placecode = 125
and place = 'Califormia'
and traveldate = 01/22/2014
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Vitor MontalvãoMSSQL Senior EngineerCommented:
You can use the format function to return only date without time.
SELECT DISTINCT PLACECODE, PLACE, format(TRAVELDATE, "mm/dd/yyyy"), CITY,  iif(QUALIFY = "YES", (TRAVELTIME/2) , TRAVELTIME),  QUALIFY
FROM YourTableName
WHERE CITY = 'Seattle'
ORDER BY PLACECODE, PLACE, TRAVELDATE 

Open in new window

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Ammar GaffarSoftware EngineerCommented:
I don't know which database engine you are using, but if you are using SQL Server then the bellow code must return only date part

SELECT CONVERT(VARCHAR(10), TRAVELDATE, 111) FROM TABLENAME

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If you are using MS Access, Vitor Montalvão's solution should work, if not the write the format in caps letter

SELECT Format([TRAVELDATE],"DD/MM/YYYY") FROM TABLENAME

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Good Luck
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Vitor MontalvãoMSSQL Senior EngineerCommented:
Even this is also in SQL Server topic it's in the question:
I am trying to create a query fo an MS Access DB that:
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Cam RabenAuthor Commented:
Vitor - An error message say that the ORDER BY clause conflicts with the DISTINCT command.   ??
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awking00Commented:
I suspect that you need to order by PLACECODE, PLACE, format(TRAVELDATE, "mm/dd/yyyy")
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Cam RabenAuthor Commented:
Thanks all!
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