Convert C++ to acceptable Arduino C++

I have the following working C++ code in GCC and want to convert it to its Arduino C++ compatible version to produce the output listed just below this code:

#include <vector>
#include <iostream>
#include <algorithm>

void fadeOn(int maxvalue, int maxlength) {
    int counter;
    int maxcounter = 1;
    int vtemp = 0;
    
    std::vector<int> v{1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}; 
    
    for (counter=1; counter < maxlength + maxvalue; counter++) {
      // simple rotation to the right
      
      std::cout << "simple rotate right " << counter << ": ";
      for (int n: v)
          std::cout << n << ' ';
      std::cout << '\n';
      
      vtemp = v[0];
      
      std::rotate(v.rbegin(), v.rbegin() + 1, v.rend());
      
      if (maxcounter < maxvalue) {
        v[0] = vtemp + 1;
      } else {
        v[0] = maxvalue;
      }
      
      maxcounter++;
    }
}

int main()
{
    fadeOn(7,13);
}

Open in new window


CURRENT OUTPUT of above code:

simple rotate right 1: 1 0 0 0 0 0 0 0 0 0 0 0 0
simple rotate right 2: 2 1 0 0 0 0 0 0 0 0 0 0 0
simple rotate right 3: 3 2 1 0 0 0 0 0 0 0 0 0 0
simple rotate right 4: 4 3 2 1 0 0 0 0 0 0 0 0 0
simple rotate right 5: 5 4 3 2 1 0 0 0 0 0 0 0 0
simple rotate right 6: 6 5 4 3 2 1 0 0 0 0 0 0 0
simple rotate right 7: 7 6 5 4 3 2 1 0 0 0 0 0 0
simple rotate right 8: 7 7 6 5 4 3 2 1 0 0 0 0 0
simple rotate right 9: 7 7 7 6 5 4 3 2 1 0 0 0 0
simple rotate right 10: 7 7 7 7 6 5 4 3 2 1 0 0 0
simple rotate right 11: 7 7 7 7 7 6 5 4 3 2 1 0 0
simple rotate right 12: 7 7 7 7 7 7 6 5 4 3 2 1 0
simple rotate right 13: 7 7 7 7 7 7 7 6 5 4 3 2 1
simple rotate right 14: 7 7 7 7 7 7 7 7 6 5 4 3 2
simple rotate right 15: 7 7 7 7 7 7 7 7 7 6 5 4 3
simple rotate right 16: 7 7 7 7 7 7 7 7 7 7 6 5 4
simple rotate right 17: 7 7 7 7 7 7 7 7 7 7 7 6 5
simple rotate right 18: 7 7 7 7 7 7 7 7 7 7 7 7 6
simple rotate right 19: 7 7 7 7 7 7 7 7 7 7 7 7 7

Now I would like to have the same outcome with Arduino C++ but I don't want to use STL libraries because I have tried and it simply makes a mess.

Any ideas?  Queues, circle buffers, ring buffers, etc... ?
LVL 1
wfninpaAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

sarabandeCommented:
you may try the following code not using stl.

#include <stdio.h>

void fadeOn(int maxvalue, int maxlength) {
    int counter;
    int maxcounter = 1;
    int vtemp = 0;
    
    int v[] = {1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}; 
    
    for (counter=1; counter < maxlength + maxvalue; counter++) {
      // simple rotation to the right
      
     printf ("simple rotate right %d", counter);
     for (int n = 0; n < 12; ++n)
          printf("%d ", n);
      printf("'\n");

      
      vtemp = v[0];
      for (int r = 11; r > 0; --r)
            v[r] = v[r-1];
      
      if (maxcounter < maxvalue) {
        v[0] = vtemp + 1;
      } else {
        v[0] = maxvalue;
      }
      
      maxcounter++;
    }
}

Open in new window


Sara
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C++

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.