How do you get the alpha value for a column

Related question:
http://www.experts-exchange.com/Software/Office_Productivity/Office_Suites/MS_Office/Excel/Q_28512271.html

I have often used the COLUMN() function to get the numeric value of a column, including in this question. Is there a way to get the alpha value for a column instead? I have currently managed it with this extremely long formula:

=ADDRESS(MATCH(RIGHT(AA33,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1)))&":$"&MID(ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1))),FIND("$",ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1))),1)+1,FIND("$",SUBSTITUTE(ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1))),"$","",1),1)-FIND("$",ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1))),1))&"$"&MATCH(RIGHT(AA33,1)+1,$Z$1:$Z$38,0)-1

This generates a cell range address:

'Charge Lines'!$AB$2:$AB$16

 The ADDRESS function provides the first section up to the colon and is then repeated within the following section to generate the same text from which to extract the value.

The section in bold gives the alpha value for the column.
CELL("filename",$A$1)  ensures the sheet name stays correct within the ADDRESS function
FIND "$" gives position of first $ within the address, the first occurence being just before the column reference so +1 for start position for MID function
SUBSTITUTE removes the first $ and then FIND gives position of second $ within the ADDRESS
Second $ less first $ gives length of column reference for number of characters in MID function.

Row numbers for ADDRESS function and then after the above extraction of column reference are achieved by using MATCH to find a week number in a different column.

Hope that explains how the above is working.

Any suggestions for making simpler. The file is Macro Enabled so would consider use of a User Defined Function.

Example file attached with cells highlighted.

Thanks
Rob H
Dummy-Time-bookings.xlsm
LVL 35
Rob HensonFinance AnalystAsked:
Who is Participating?
 
Rgonzo1971Commented:
pls try

=ADDRESS(MATCH(RIGHT(AA33,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1)))&":"&SUBSTITUTE(ADDRESS(1,COLUMN(),1,),"1","")&MATCH(RIGHT(AA33,1)+1,$Z$1:$Z$38,0)-1
0
 
Rgonzo1971Commented:
Hi,

pls try for example

=LEFT(ADDRESS(1,COLUMN(AA39),4,),LEN(ADDRESS(1,COLUMN(AA39),4))-1)

EDIT for your example

you could use LEFT(ADDRESS(1,COLUMN(AA39),1,),LEN(ADDRESS(1,COLUMN(AA39),1))-1) to eliminate the need of the "$"

Regards
0
 
Rgonzo1971Commented:
Shorter

=SUBSTITUTE(ADDRESS(1,COLUMN(AA39),4,),"1","")
'OR
=SUBSTITUTE(ADDRESS(1,COLUMN(AA39),1,),"1","")
0
Free Tool: Path Explorer

An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

 
Rob HensonFinance AnalystAuthor Commented:
Sorry,I am not understanding how the above suggestions would be incorporated into the formula. Please can you post the whole formula.

Thanks
Rob H
0
 
Rob HensonFinance AnalystAuthor Commented:
Actually, got it figured out.

=ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1)))&LEFT(ADDRESS(1,COLUMN(AB34),1,),LEN(ADDRESS(1,COLUMN(AB34),1))-1)&MATCH(RIGHT(AA34,1)+1,$Z$1:$Z$38)

Bizarrely enough, eventhough the above is in cell AB34, reference to AB34 within the formula doesn't result in a circular reference.

Much shorter than original. Amazing what another pair of eyes can do to change the logic path; I am normally not too bad for thinking outside of the box (if the box even exists??), I obviously got trapped within it on this occasion.

Thanks
Rob H
0
 
Rgonzo1971Commented:
it is not a circular reference because you do not use the value of the cell but its position
0
 
Rgonzo1971Commented:
a bit shorter

=ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1)))&":"&ADDRESS(MATCH(RIGHT(AA34,1)+1,$Z$1:$Z$38),COLUMN(AB34),1)
0
 
Rob HensonFinance AnalystAuthor Commented:
Going with this one for Week 1:

=ADDRESS(MATCH(RIGHT(AA33,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1)))&":"&SUBSTITUTE(ADDRESS(1,COLUMN(),1,),"1","")&MATCH(RIGHT(AA33,1)+1,$Z$1:$Z$38,0)-1

and a slight tweak for Week 2:

=ADDRESS(MATCH(RIGHT(AA34,1)*1,$Z$1:$Z$38,0),COLUMN(),1,1,RIGHT(CELL("filename",$A$1),LEN(CELL("filename",$A$1))-FIND("]",CELL("filename",$A$1),1)))&":"&SUBSTITUTE(ADDRESS(1,COLUMN(),1,),"1","")&MATCH(RIGHT(AA34,1)+1,$Z$1:$Z$38)

Difference being the non-exact MATCH at the end finding the last occurence of 2 because it can't find 3.

Thanks
Rob H
0
 
Rob HensonFinance AnalystAuthor Commented:
Thank you for your continued support.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.