Dos Command file file access

I want to make a dos command line (.bat, .cmd) file that takes first argment and then


creates a filename containing % 1 and then creates and opens a new filename file  and writes to it a string that will also contain %1
smcsmc1Asked:
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BeartlaoiCommented:
The shortest way to do that is
echo some text %1 more text >file%1.txt

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smcsmc1Author Commented:
very good, I was trying to use the type cmd instead of echo, thanks
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