How to create a parametrized MySQL table?

Hi Expets!

Do you know a way to create a table with a name received as a parameter, inside a stored procedure?

by example:

CALL sp_pesquisa_lancamentos ("20140901","20140919",4,"the_name_I_want_for_the_table_to_be_created");

PROCEDURE sp_pesquisa_lancamentos (IN dt_ini date, IN dt_fim date, IN s_emp integer(11), IN  tabela varchar(20))

 CREATE TABLE  [tabela](
    Id int(6) NULL,
    CR varchar(50) NULL,
    DSP varchar(50) NULL,
    CT varchar(50) NULL,
    DCN varchar(10) NULL,
    DIA varchar(12) NULL,
    DT_LAN varchar(12) NULL,
    VALOR varchar(15) NULL,
    QTD varchar(5) NULL,
    DESTINO varchar(100) NULL,
    SALDO_C varchar(15) NULL,
    EMP varchar(10) NULL,
    ORIGEM  varchar(10) NULL


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Thanks in advance!
Eduardo FuerteDeveloper and AnalystAsked:
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ste5anSenior DeveloperCommented:
You need dynamic SQL with PREPARE and EXECUTE. Concat the table name into the prepare statement. A table name as parameter is not supported.


PROCEDURE sp_pesquisa_lancamentos (
	IN dt_ini DATE, 
	IN dt_fim DATE, 
	IN s_emp INTEGER(11), 
	IN  tabela VARCHAR(20)

	SET @Sql = CONCAT( "DROP TABLE IF EXISTS ", tabela, ";");
	PREPARE preparedStmt FROM @Sql;
	EXECUTE preparedStmt;


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Caveat: Cause you need string concatenation, this is prone to SQL injection. Consider a different approach, when posssible. Look for multitenant  solutions. E.g. use a discriminator in one big table instead of separate tables.

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Eduardo FuerteDeveloper and AnalystAuthor Commented:

By using this approach I solved all the issues

Drop table
create table

Thank you very much!
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