Determine differeing column

Hi,
I am using except to return the differing rows in two select statements.
How would I be able to determine which column(s) is the different?

SELECT      Col1,
            Col2,
            Col3,
            Col4,
            Col5
FROM      Table1
EXCEPT
SELECT      Col1,
            Col2,
            Col3,
            Col4,
            Col5
FROM      Table2

Thanks
Morpheus7Asked:
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Phillip BurtonDirector, Practice Manager and Computing ConsultantCommented:
I'm afraid your question does not give all the information I need to answer it fully. Whether a column is numeric, or a date, or a varchar is important.

I am going to assume that Col1 is your primary key, and it is the same between Table1 and Table2.

Here's my answer:

select T.col1, T.col2, T.col3, T.col4, T.col5,
iif(T.col2<>U.col2,1,0) as Col2Different, 
iif(T.col3<>U.col3,1,0) as Col3Different, 
iif(T.col4<>U.col4,1,0) as Col4Different, 
iif(T.col5<>U.col5,1,0) as Col5Different
from table1 T
left join table2 U
on T.col1 = U.col1

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0
Morpheus7Author Commented:
Many thanks for the reply. Col1 is the primary key and the others are varchar with the exception being col5 which is int.
0
Phillip BurtonDirector, Practice Manager and Computing ConsultantCommented:
Are any of the columns nullable?
0
Morpheus7Author Commented:
Hi,

With the exception of Col1, they could be nullable
Thanks
0
Phillip BurtonDirector, Practice Manager and Computing ConsultantCommented:
Here's my updated answer. It shows 0 if there is no difference, 1 if there is a difference, and 2 if the row is new:

select T.col1, T.col2, T.col3, T.col4, T.col5,
iif(coalesce(T.col2,'')<>coalesce(U.col2,''),iif(U.col2 is null,2,1),0) as Col2Different, 
iif(coalesce(T.col3,'')<>coalesce(U.col3,''),iif(U.col3 is null,2,1),0) as Col3Different, 
iif(coalesce(T.col4,'')<>coalesce(U.col4,''),iif(U.col4 is null,2,1),0) as Col4Different, 
iif(coalesce(T.col5,-2147483648)<>coalesce(U.col5,-2147483648),iif(U.col5 is null,2,1),0) as Col5Different
from table1 T
left join table2 U
on T.col1 = U.col1

Open in new window

0

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