Still celebrating National IT Professionals Day with 3 months of free Premium Membership. Use Code ITDAY17

x
?
Solved

SQL Find Customers who have not paid 100

Posted on 2014-09-23
6
Medium Priority
?
122 Views
Last Modified: 2014-09-23
Hi
I have a Customers table and a Payments table, shown in that order below
What joined query would I use to find the CustID of those Customers who have
not paid an AMOUNT of 100. The [LINK ID] is the same as the CustID in CUSTOMERS

Customers
Payments
0
Comment
Question by:Murray Brown
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
6 Comments
 
LVL 70

Expert Comment

by:Scott Pletcher
ID: 40339265
SELECT c.*
FROM (
    SELECT [Link Id]
    FROM Payments
    GROUP BY p.[Link Id]
    HAVING MAX(CASE WHEN Amount = 100.00 THEN 1 ELSE 0 END) = 0
) AS p
INNER JOIN Customers c ON
    c.CustID = p.[Link Id]
0
 
LVL 66

Expert Comment

by:Jim Horn
ID: 40339269
btw, you might have the image labels off, as the set labeled 'Customers' looks like a payments table, and vise versa

Looks like Scott answered it above.

Also, do yourself a favor and lose the spaces in the First Name, Last Name columns, as it forces T-SQL to delineate it using square brackets [ ], which is one thing to potentially forget and throw an error.
0
 
LVL 24

Expert Comment

by:Phillip Burton
ID: 40339270
I assume that these two tables are the wrong way round - the first one should be payments and the customers.

Select C.CustID, C.[First Name], C.[Last Name], Sum(Amount) as TotalAmount
From Customers C
LEFT JOIN Payments P
ON C.CustID = P.[LINK ID]
GROUP BY C.CustID, C.[First Name], C.[Last Name]
HAVING Sum(Amount) < 100 OR P.[LINK ID] IS NULL

Open in new window

0
Survive A High-Traffic Event with Percona

Your application or website rely on your database to deliver information about products and services to your customers. You can’t afford to have your database lose performance, lose availability or become unresponsive – even for just a few minutes.

 

Author Comment

by:Murray Brown
ID: 40339315
Hi
Yes the two tables are the wrong way around. I was looking for Customers who have not paid the amount of 100 once(not in total).
0
 
LVL 24

Accepted Solution

by:
Phillip Burton earned 2000 total points
ID: 40339324
Select C.CustID, C.[First Name], C.[Last Name], Max(Amount) as MaxAmount
From Customers C
LEFT JOIN Payments P
ON C.CustID = P.[LINK ID]
WHERE Max(Amount) < 100 OR P.[LINK ID] IS NULL
GROUP BY C.CustID, C.[First Name], C.[Last Name]

Open in new window

0
 

Author Closing Comment

by:Murray Brown
ID: 40339784
Thanks for the help
0

Featured Post

Free Tool: Path Explorer

An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

For both online and offline retail, the cross-channel business is the most recent pattern in the B2C trade space.
It is possible to export the data of a SQL Table in SSMS and generate INSERT statements. It's neatly tucked away in the generate scripts option of a database.
This video shows, step by step, how to configure Oracle Heterogeneous Services via the Generic Gateway Agent in order to make a connection from an Oracle session and access a remote SQL Server database table.
Via a live example, show how to shrink a transaction log file down to a reasonable size.

705 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question